添加 卡码网0110.字符串接龙 JS版

problems/kamacoder/0110.字符串接龙.md

@@ -224,6 +224,80 @@ public class Main {
 
 ### Javascript
 
+```javascript
+const r1 = require('readline').createInterface({ input: process.stdin });
+// 创建readline接口
+let iter = r1[Symbol.asyncIterator]();
+// 创建异步迭代器
+const readline = async () => (await iter.next()).value;
+
+let N //输入字符串个数
+let beginStr //开始字符串
+let endStr //结束字符串
+let strSet = new Set() //字符串集合
+let visitedMap = new Map() //访问过的字符串
+
+// 读取输入，初始化地图
+const init = async () => {
+  let line = await readline();
+  line = line.trim()
+  N = Number(line);
+
+  line = await readline();
+  line = line.trim().split(' ')
+  beginStr = line[0]
+  endStr = line[1]
+
+  for (let i = 0; i < N; i++) {
+    line = await readline()
+    line = line.trim()
+    strSet.add(line.trim())
+  }
+}
+
+(async function () {
+
+  // 读取输入，初始化数据
+  await init()
+
+  // 初始化队列
+  let queue = []
+  queue.push(beginStr)
+
+  // 初始化visitMap
+  visitedMap.set(beginStr, 1)
+
+  while (queue.length) {
+    let word = queue.shift()
+    let path = visitedMap.get(word)
+
+    // 遍历26个字母
+    for (let i = 0; i < word.length; i++) {
+      let newWord = word.split('') // 用一个新字符串替换str，因为每次要置换一个字符
+      for (let j = 0; j < 26; j++) {
+        newWord[i] = String.fromCharCode('a'.charCodeAt() + j)
+        // 发现替换字母后，字符串与终点字符串相同
+        if (newWord.join('') === endStr) {
+          console.log(path + 1);
+          return 0;   // 找到了路径 
+        }
+
+        // 字符串集合里出现了newWord，并且newWord没有被访问过
+        if (strSet.has(newWord.join('')) && !visitedMap.has(newWord.join(''))) {
+          // 添加访问信息，并将新字符串放到队列中
+          queue.push(newWord.join(''))
+          visitedMap.set(newWord.join(''), path + 1)
+        }
+      }
+    }
+  }
+
+  console.log(0);
+})()
+```
+
+
+
 ### TypeScript
 
 ### PhP