From 7bbf3827d1b9aa3a18f4073533ac2934ecc4eab1 Mon Sep 17 00:00:00 2001
From: Lane Zhang <zjloveztt@gmail.com>
Date: Wed, 16 Oct 2024 14:20:41 +0800
Subject: [PATCH] =?UTF-8?q?0151.=E7=BF=BB=E8=BD=AC=E5=AD=97=E7=AC=A6?=
 =?UTF-8?q?=E4=B8=B2=E9=87=8C=E7=9A=84=E5=8D=95=E8=AF=8D=20=E5=A2=9E?=
 =?UTF-8?q?=E5=8A=A0Python=E7=89=88=E6=9C=AC=E5=AE=9E=E7=8E=B05?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 problems/0151.翻转字符串里的单词.md | 23 ++++++++++++++++++++
 1 file changed, 23 insertions(+)

diff --git a/problems/0151.翻转字符串里的单词.md b/problems/0151.翻转字符串里的单词.md
index 9a0cbea4..7c0b7cb1 100644
--- a/problems/0151.翻转字符串里的单词.md
+++ b/problems/0151.翻转字符串里的单词.md
@@ -513,6 +513,29 @@ class Solution:
 
         return "".join(result)
 ```
+
+(版本五) 遇到空格就说明前面的是一个单词，把它加入到一个数组中。
+
+```python
+class Solution:
+    def reverseWords(self, s: str) -> str:
+        words = []
+        word = ''
+        s += ' ' # 帮助处理最后一个字词
+
+        for char in s:
+            if char == ' ': # 遇到空格就说明前面的可能是一个单词
+                if word != '': # 确认是单词，把它加入到一个数组中
+                    words.append(word)
+                    word = '' # 清空当前单词
+                continue
+            
+            word += char # 收集单词的字母
+        
+        words.reverse()
+        return ' '.join(words)
+```
+
 ### Go：
 
 版本一：