Restructure folders.

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Oleksii Trekhleb
2018-04-26 07:26:12 +03:00
parent 9bef8de6b1
commit c62a6ceabf
20 changed files with 9 additions and 8 deletions

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# Combinations
When the order doesn't matter, it is a **Combination**.
When the order **does** matter it is a **Permutation**.
**"My fruit salad is a combination of apples, grapes and bananas"**
We don't care what order the fruits are in, they could also be
"bananas, grapes and apples" or "grapes, apples and bananas",
its the same fruit salad.
## Combinations without repetitions
This is how lotteries work. The numbers are drawn one at a
time, and if we have the lucky numbers (no matter what order)
we win!
No Repetition: such as lottery numbers `(2,14,15,27,30,33)`
**Number of combinations**
![Formula](https://www.mathsisfun.com/combinatorics/images/combinations-no-repeat.png)
where `n` is the number of things to choose from, and we choose `r` of them,
no repetition, order doesn't matter.
It is often called "n choose r" (such as "16 choose 3"). And is also known as the Binomial Coefficient.
## Combinations with repetitions
Repetition is Allowed: such as coins in your pocket `(5,5,5,10,10)`
Or let us say there are five flavours of icecream:
`banana`, `chocolate`, `lemon`, `strawberry` and `vanilla`.
We can have three scoops. How many variations will there be?
Let's use letters for the flavours: `{b, c, l, s, v}`.
Example selections include:
- `{c, c, c}` (3 scoops of chocolate)
- `{b, l, v}` (one each of banana, lemon and vanilla)
- `{b, v, v}` (one of banana, two of vanilla)
**Number of combinations**
![Formula](https://www.mathsisfun.com/combinatorics/images/combinations-repeat.gif)
Where `n` is the number of things to choose from, and we
choose `r` of them. Repetition allowed,
order doesn't matter.
## References
[Math Is Fun](https://www.mathsisfun.com/combinatorics/combinations-permutations.html)

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import combineWithRepetitions from '../combineWithRepetitions';
import factorial from '../../../math/factorial/factorial';
describe('combineWithRepetitions', () => {
it('should combine string with repetitions', () => {
expect(combineWithRepetitions(['A'], 1)).toEqual([
['A'],
]);
expect(combineWithRepetitions(['A', 'B'], 1)).toEqual([
['A'],
['B'],
]);
expect(combineWithRepetitions(['A', 'B'], 2)).toEqual([
['A', 'A'],
['A', 'B'],
['B', 'B'],
]);
expect(combineWithRepetitions(['A', 'B'], 3)).toEqual([
['A', 'A', 'A'],
['A', 'A', 'B'],
['A', 'B', 'B'],
['B', 'B', 'B'],
]);
expect(combineWithRepetitions(['A', 'B', 'C'], 2)).toEqual([
['A', 'A'],
['A', 'B'],
['A', 'C'],
['B', 'B'],
['B', 'C'],
['C', 'C'],
]);
expect(combineWithRepetitions(['A', 'B', 'C'], 3)).toEqual([
['A', 'A', 'A'],
['A', 'A', 'B'],
['A', 'A', 'C'],
['A', 'B', 'B'],
['A', 'B', 'C'],
['A', 'C', 'C'],
['B', 'B', 'B'],
['B', 'B', 'C'],
['B', 'C', 'C'],
['C', 'C', 'C'],
]);
const combinationOptions = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H'];
const combinationSlotsNumber = 4;
const combinations = combineWithRepetitions(combinationOptions, combinationSlotsNumber);
const n = combinationOptions.length;
const r = combinationSlotsNumber;
const expectedNumberOfCombinations = factorial((r + n) - 1) / (factorial(r) * factorial(n - 1));
expect(combinations.length).toBe(expectedNumberOfCombinations);
});
});

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import combineWithoutRepetitions from '../combineWithoutRepetitions';
import factorial from '../../../math/factorial/factorial';
describe('combineWithoutRepetitions', () => {
it('should combine string without repetitions', () => {
expect(combineWithoutRepetitions(['A', 'B'], 3)).toEqual([]);
expect(combineWithoutRepetitions(['A', 'B'], 1)).toEqual([
['A'],
['B'],
]);
expect(combineWithoutRepetitions(['A'], 1)).toEqual([
['A'],
]);
expect(combineWithoutRepetitions(['A', 'B'], 2)).toEqual([
['A', 'B'],
]);
expect(combineWithoutRepetitions(['A', 'B', 'C'], 2)).toEqual([
['A', 'B'],
['A', 'C'],
['B', 'C'],
]);
expect(combineWithoutRepetitions(['A', 'B', 'C'], 3)).toEqual([
['A', 'B', 'C'],
]);
expect(combineWithoutRepetitions(['A', 'B', 'C', 'D'], 3)).toEqual([
['A', 'B', 'C'],
['A', 'B', 'D'],
['A', 'C', 'D'],
['B', 'C', 'D'],
]);
expect(combineWithoutRepetitions(['A', 'B', 'C', 'D', 'E'], 3)).toEqual([
['A', 'B', 'C'],
['A', 'B', 'D'],
['A', 'B', 'E'],
['A', 'C', 'D'],
['A', 'C', 'E'],
['A', 'D', 'E'],
['B', 'C', 'D'],
['B', 'C', 'E'],
['B', 'D', 'E'],
['C', 'D', 'E'],
]);
const combinationOptions = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H'];
const combinationSlotsNumber = 4;
const combinations = combineWithoutRepetitions(combinationOptions, combinationSlotsNumber);
const n = combinationOptions.length;
const r = combinationSlotsNumber;
const expectedNumberOfCombinations = factorial(n) / (factorial(r) * factorial(n - r));
expect(combinations.length).toBe(expectedNumberOfCombinations);
});
});

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/**
* @param {*[]} combinationOptions
* @param {number} combinationLength
* @return {*[]}
*/
export default function combineWithRepetitions(combinationOptions, combinationLength) {
// If combination length equal to 0 then return empty combination.
if (combinationLength === 0) {
return [[]];
}
// If combination options are empty then return "no-combinations" array.
if (combinationOptions.length === 0) {
return [];
}
// Init combinations array.
const combos = [];
// Find all shorter combinations and attach head to each of those.
const headCombo = [combinationOptions[0]];
const shorterCombos = combineWithRepetitions(combinationOptions, combinationLength - 1);
for (let combinationIndex = 0; combinationIndex < shorterCombos.length; combinationIndex += 1) {
const combo = headCombo.concat(shorterCombos[combinationIndex]);
combos.push(combo);
}
// Let's shift head to the right and calculate all the rest combinations.
const combinationsWithoutHead = combineWithRepetitions(
combinationOptions.slice(1),
combinationLength,
);
// Join all combinations and return them.
return combos.concat(combinationsWithoutHead);
}

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/*
@see: https://stackoverflow.com/a/127898/7794070
Lets say your array of letters looks like this: "ABCDEFGH".
You have three indices (i, j, k) indicating which letters you
are going to use for the current word, You start with:
A B C D E F G H
^ ^ ^
i j k
First you vary k, so the next step looks like that:
A B C D E F G H
^ ^ ^
i j k
If you reached the end you go on and vary j and then k again.
A B C D E F G H
^ ^ ^
i j k
A B C D E F G H
^ ^ ^
i j k
Once you j reached G you start also to vary i.
A B C D E F G H
^ ^ ^
i j k
A B C D E F G H
^ ^ ^
i j k
...
*/
/**
* @param {*[]} combinationOptions
* @param {number} combinationLength
* @return {*[]}
*/
export default function combineWithoutRepetitions(combinationOptions, combinationLength) {
// If combination length is just 1 then return combinationOptions.
if (combinationLength === 1) {
return combinationOptions.map(option => [option]);
}
// Init combinations array.
const combinations = [];
for (let i = 0; i <= (combinationOptions.length - combinationLength); i += 1) {
const smallerCombinations = combineWithoutRepetitions(
combinationOptions.slice(i + 1),
combinationLength - 1,
);
for (let j = 0; j < smallerCombinations.length; j += 1) {
const combination = [combinationOptions[i]].concat(smallerCombinations[j]);
combinations.push(combination);
}
}
// Return all calculated combinations.
return combinations;
}