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src/algorithms/math/complex-number/README.md
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src/algorithms/math/complex-number/README.md
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# Complex Number
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A **complex number** is a number that can be expressed in the
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form `a + b * i`, where `a` and `b` are real numbers, and `i` is a solution of
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the equation `x^2 = −1`. Because no *real number* satisfies this
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equation, `i` is called an *imaginary number*. For the complex
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number `a + b * i`, `a` is called the *real part*, and `b` is called
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the *imaginary part*.
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A Complex Number is a combination of a Real Number and an Imaginary Number:
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Geometrically, complex numbers extend the concept of the one-dimensional number
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line to the *two-dimensional complex plane* by using the horizontal axis for the
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real part and the vertical axis for the imaginary part. The complex
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number `a + b * i` can be identified with the point `(a, b)` in the complex plane.
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A complex number whose real part is zero is said to be *purely imaginary*; the
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points for these numbers lie on the vertical axis of the complex plane. A complex
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number whose imaginary part is zero can be viewed as a *real number*; its point
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lies on the horizontal axis of the complex plane.
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| Complex Number | Real Part | Imaginary Part | |
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| :------------- | :-------: | :------------: | --- |
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| 3 + 2i | 3 | 2 | |
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| 5 | 5 | **0** | Purely Real |
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| −6i | **0** | -6 | Purely Imaginary |
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A complex number can be visually represented as a pair of numbers `(a, b)` forming
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a vector on a diagram called an *Argand diagram*, representing the *complex plane*.
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`Re` is the real axis, `Im` is the imaginary axis, and `i` satisfies `i^2 = −1`.
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> Complex does not mean complicated. It means the two types of numbers, real and
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imaginary, together form a complex, just like a building complex (buildings
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joined together).
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## Basic Operations
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### Adding
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To add two complex numbers we add each part separately:
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```text
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(a + b * i) + (c + d * i) = (a + c) + (b + d) * i
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```
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**Example**
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```text
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(3 + 5i) + (4 − 3i) = (3 + 4) + (5 − 3)i = 7 + 2i
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```
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On complex plane the adding operation will look like the following:
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### Subtracting
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To subtract two complex numbers we subtract each part separately:
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```text
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(a + b * i) - (c + d * i) = (a - c) + (b - d) * i
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```
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**Example**
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```text
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(3 + 5i) - (4 − 3i) = (3 - 4) + (5 + 3)i = -1 + 8i
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```
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### Multiplying
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To multiply complex numbers each part of the first complex number gets multiplied
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by each part of the second complex number:
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Just use "FOIL", which stands for "**F**irsts, **O**uters, **I**nners, **L**asts" (
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see [Binomial Multiplication](ttps://www.mathsisfun.com/algebra/polynomials-multiplying.html) for
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more details):
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- Firsts: `a × c`
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- Outers: `a × di`
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- Inners: `bi × c`
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- Lasts: `bi × di`
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In general it looks like this:
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```text
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(a + bi)(c + di) = ac + adi + bci + bdi^2
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```
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But there is also a quicker way!
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Use this rule:
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```text
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(a + bi)(c + di) = (ac − bd) + (ad + bc)i
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```
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**Example**
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```text
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(3 + 2i)(1 + 7i)
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= 3×1 + 3×7i + 2i×1+ 2i×7i
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= 3 + 21i + 2i + 14i^2
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= 3 + 21i + 2i − 14 (because i^2 = −1)
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= −11 + 23i
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```
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```text
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(3 + 2i)(1 + 7i) = (3×1 − 2×7) + (3×7 + 2×1)i = −11 + 23i
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```
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### Conjugates
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We will need to know about conjugates in a minute!
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A conjugate is where we change the sign in the middle like this:
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A conjugate is often written with a bar over it:
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```text
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______
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5 − 3i = 5 + 3i
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```
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On the complex plane the conjugate number will be mirrored against real axes.
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### Dividing
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The conjugate is used to help complex division.
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The trick is to *multiply both top and bottom by the conjugate of the bottom*.
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**Example**
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```text
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2 + 3i
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------
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4 − 5i
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```
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Multiply top and bottom by the conjugate of `4 − 5i`:
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```text
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(2 + 3i) * (4 + 5i) 8 + 10i + 12i + 15i^2
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= ------------------- = ----------------------
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(4 − 5i) * (4 + 5i) 16 + 20i − 20i − 25i^2
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```
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Now remember that `i^2 = −1`, so:
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```text
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8 + 10i + 12i − 15 −7 + 22i −7 22
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= ------------------- = -------- = -- + -- * i
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16 + 20i − 20i + 25 41 41 41
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```
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There is a faster way though.
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In the previous example, what happened on the bottom was interesting:
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```text
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(4 − 5i)(4 + 5i) = 16 + 20i − 20i − 25i
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```
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The middle terms `(20i − 20i)` cancel out! Also `i^2 = −1` so we end up with this:
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```text
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(4 − 5i)(4 + 5i) = 4^2 + 5^2
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```
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Which is really quite a simple result. The general rule is:
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```text
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(a + bi)(a − bi) = a^2 + b^2
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```
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## References
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- [Wikipedia](https://en.wikipedia.org/wiki/Complex_number)
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- [Math is Fun](https://www.mathsisfun.com/numbers/complex-numbers.html)
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