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	* .net 8.0 migration * update docs * revert change * revert change and update appendix docs * remove static * Update binary_search_insertion.cs * Update binary_search_insertion.cs * Update binary_search_edge.cs * Update binary_search_insertion.cs * Update binary_search_edge.cs --------- Co-authored-by: Yudong Jin <krahets@163.com>
		
			
				
	
	
		
			54 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			C#
		
	
	
	
	
	
			
		
		
	
	
			54 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			C#
		
	
	
	
	
	
/**
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* File: coin_change_greedy.cs
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* Created Time: 2023-07-21
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* Author: hpstory (hpstory1024@163.com)
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*/
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namespace hello_algo.chapter_greedy;
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public class coin_change_greedy {
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    /* 零钱兑换:贪心 */
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    int CoinChangeGreedy(int[] coins, int amt) {
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        // 假设 coins 列表有序
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        int i = coins.Length - 1;
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        int count = 0;
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        // 循环进行贪心选择,直到无剩余金额
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        while (amt > 0) {
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            // 找到小于且最接近剩余金额的硬币
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            while (i > 0 && coins[i] > amt) {
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                i--;
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            }
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            // 选择 coins[i]
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            amt -= coins[i];
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            count++;
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        }
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        // 若未找到可行方案,则返回 -1
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        return amt == 0 ? count : -1;
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    }
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    [Test]
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    public void Test() {
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        // 贪心:能够保证找到全局最优解
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        int[] coins = [1, 5, 10, 20, 50, 100];
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        int amt = 186;
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        int res = CoinChangeGreedy(coins, amt);
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        Console.WriteLine("\ncoins = " + coins.PrintList() + ", amt = " + amt);
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        Console.WriteLine("凑到 " + amt + " 所需的最少硬币数量为 " + res);
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        // 贪心:无法保证找到全局最优解
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        coins = [1, 20, 50];
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        amt = 60;
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        res = CoinChangeGreedy(coins, amt);
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        Console.WriteLine("\ncoins = " + coins.PrintList() + ", amt = " + amt);
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        Console.WriteLine("凑到 " + amt + " 所需的最少硬币数量为 " + res);
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        Console.WriteLine("实际上需要的最少数量为 3 ,即 20 + 20 + 20");
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        // 贪心:无法保证找到全局最优解
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        coins = [1, 49, 50];
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        amt = 98;
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        res = CoinChangeGreedy(coins, amt);
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        Console.WriteLine("\ncoins = " + coins.PrintList() + ", amt = " + amt);
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        Console.WriteLine("凑到 " + amt + " 所需的最少硬币数量为 " + res);
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        Console.WriteLine("实际上需要的最少数量为 2 ,即 49 + 49");
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    }
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} |