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			61 lines
		
	
	
		
			2.2 KiB
		
	
	
	
		
			Java
		
	
	
	
	
	
			
		
		
	
	
			61 lines
		
	
	
		
			2.2 KiB
		
	
	
	
		
			Java
		
	
	
	
	
	
/**
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 * File: subset_sum_ii.java
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 * Created Time: 2023-06-21
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 * Author: krahets (krahets@163.com)
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 */
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package chapter_backtracking;
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import java.util.*;
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public class subset_sum_ii {
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    /* 回溯算法:子集和 II */
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    static void backtrack(List<Integer> state, int target, int[] choices, int start, List<List<Integer>> res) {
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        // 子集和等于 target 时,记录解
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        if (target == 0) {
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            res.add(new ArrayList<>(state));
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            return;
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        }
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        // 遍历所有选择
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        // 剪枝二:从 start 开始遍历,避免生成重复子集
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        // 剪枝三:从 start 开始遍历,避免重复选择同一元素
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        for (int i = start; i < choices.length; i++) {
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            // 剪枝一:若子集和超过 target ,则直接结束循环
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            // 这是因为数组已排序,后边元素更大,子集和一定超过 target
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            if (target - choices[i] < 0) {
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                break;
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            }
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            // 剪枝四:如果该元素与左边元素相等,说明该搜索分支重复,直接跳过
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            if (i > start && choices[i] == choices[i - 1]) {
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                continue;
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            }
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            // 尝试:做出选择,更新 target, start
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            state.add(choices[i]);
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            // 进行下一轮选择
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            backtrack(state, target - choices[i], choices, i + 1, res);
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            // 回退:撤销选择,恢复到之前的状态
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            state.remove(state.size() - 1);
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        }
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    }
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    /* 求解子集和 II */
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    static List<List<Integer>> subsetSumII(int[] nums, int target) {
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        List<Integer> state = new ArrayList<>(); // 状态(子集)
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        Arrays.sort(nums); // 对 nums 进行排序
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        int start = 0; // 遍历起始点
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        List<List<Integer>> res = new ArrayList<>(); // 结果列表(子集列表)
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        backtrack(state, target, nums, start, res);
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        return res;
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    }
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    public static void main(String[] args) {
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        int[] nums = { 4, 4, 5 };
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        int target = 9;
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        List<List<Integer>> res = subsetSumII(nums, target);
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        System.out.println("输入数组 nums = " + Arrays.toString(nums) + ", target = " + target);
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        System.out.println("所有和等于 " + target + " 的子集 res = " + res);
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    }
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}
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