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			128 lines
		
	
	
		
			4.0 KiB
		
	
	
	
		
			C#
		
	
	
	
	
	
			
		
		
	
	
			128 lines
		
	
	
		
			4.0 KiB
		
	
	
	
		
			C#
		
	
	
	
	
	
/**
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* File: min_path_sum.cs
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* Created Time: 2023-07-10
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* Author: hpstory (hpstory1024@163.com)
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*/
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namespace hello_algo.chapter_dynamic_programming;
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public class min_path_sum {
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    /* 最小路径和:暴力搜索 */
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    int MinPathSumDFS(int[][] grid, int i, int j) {
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        // 若为左上角单元格,则终止搜索
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        if (i == 0 && j == 0) {
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            return grid[0][0];
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        }
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        // 若行列索引越界,则返回 +∞ 代价
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        if (i < 0 || j < 0) {
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            return int.MaxValue;
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        }
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        // 计算从左上角到 (i-1, j) 和 (i, j-1) 的最小路径代价
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        int up = MinPathSumDFS(grid, i - 1, j);
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        int left = MinPathSumDFS(grid, i, j - 1);
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        // 返回从左上角到 (i, j) 的最小路径代价
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        return Math.Min(left, up) + grid[i][j];
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    }
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    /* 最小路径和:记忆化搜索 */
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    int MinPathSumDFSMem(int[][] grid, int[][] mem, int i, int j) {
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        // 若为左上角单元格,则终止搜索
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        if (i == 0 && j == 0) {
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            return grid[0][0];
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        }
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        // 若行列索引越界,则返回 +∞ 代价
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        if (i < 0 || j < 0) {
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            return int.MaxValue;
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        }
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        // 若已有记录,则直接返回
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        if (mem[i][j] != -1) {
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            return mem[i][j];
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        }
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        // 左边和上边单元格的最小路径代价
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        int up = MinPathSumDFSMem(grid, mem, i - 1, j);
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        int left = MinPathSumDFSMem(grid, mem, i, j - 1);
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        // 记录并返回左上角到 (i, j) 的最小路径代价
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        mem[i][j] = Math.Min(left, up) + grid[i][j];
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        return mem[i][j];
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    }
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    /* 最小路径和:动态规划 */
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    int MinPathSumDP(int[][] grid) {
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        int n = grid.Length, m = grid[0].Length;
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        // 初始化 dp 表
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        int[,] dp = new int[n, m];
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        dp[0, 0] = grid[0][0];
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        // 状态转移:首行
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        for (int j = 1; j < m; j++) {
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            dp[0, j] = dp[0, j - 1] + grid[0][j];
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        }
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        // 状态转移:首列
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        for (int i = 1; i < n; i++) {
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            dp[i, 0] = dp[i - 1, 0] + grid[i][0];
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        }
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        // 状态转移:其余行和列
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        for (int i = 1; i < n; i++) {
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            for (int j = 1; j < m; j++) {
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                dp[i, j] = Math.Min(dp[i, j - 1], dp[i - 1, j]) + grid[i][j];
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            }
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        }
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        return dp[n - 1, m - 1];
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    }
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    /* 最小路径和:空间优化后的动态规划 */
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    int MinPathSumDPComp(int[][] grid) {
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        int n = grid.Length, m = grid[0].Length;
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        // 初始化 dp 表
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        int[] dp = new int[m];
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        dp[0] = grid[0][0];
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        // 状态转移:首行
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        for (int j = 1; j < m; j++) {
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            dp[j] = dp[j - 1] + grid[0][j];
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        }
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        // 状态转移:其余行
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        for (int i = 1; i < n; i++) {
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            // 状态转移:首列
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            dp[0] = dp[0] + grid[i][0];
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            // 状态转移:其余列
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            for (int j = 1; j < m; j++) {
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                dp[j] = Math.Min(dp[j - 1], dp[j]) + grid[i][j];
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            }
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        }
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        return dp[m - 1];
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    }
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    [Test]
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    public void Test() {
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        int[][] grid =
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        [
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            [1, 3, 1, 5],
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            [2, 2, 4, 2],
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            [5, 3, 2, 1],
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            [4, 3, 5, 2]
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        ];
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        int n = grid.Length, m = grid[0].Length;
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        // 暴力搜索
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        int res = MinPathSumDFS(grid, n - 1, m - 1);
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        Console.WriteLine("从左上角到右下角的最小路径和为 " + res);
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        // 记忆化搜索
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        int[][] mem = new int[n][];
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        for (int i = 0; i < n; i++) {
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            mem[i] = new int[m];
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            Array.Fill(mem[i], -1);
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        }
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        res = MinPathSumDFSMem(grid, mem, n - 1, m - 1);
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        Console.WriteLine("从左上角到右下角的最小路径和为 " + res);
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        // 动态规划
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        res = MinPathSumDP(grid);
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        Console.WriteLine("从左上角到右下角的最小路径和为 " + res);
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        // 空间优化后的动态规划
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        res = MinPathSumDPComp(grid);
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        Console.WriteLine("从左上角到右下角的最小路径和为 " + res);
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    }
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}
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