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	* fix: check the rust codes and fix it * Update binary_tree_bfs.rs --------- Co-authored-by: Yudong Jin <krahets@163.com>
		
			
				
	
	
		
			52 lines
		
	
	
		
			1.5 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
			
		
		
	
	
			52 lines
		
	
	
		
			1.5 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
/*
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 * File: linear_search.rs
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 * Created Time: 2023-07-09
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 * Author: sjinzh (sjinzh@gmail.com)
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 */
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 include!("../include/include.rs");
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 use std::rc::Rc;
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 use std::cell::RefCell;
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 use list_node::ListNode;
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/* 线性查找(数组) */
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fn linear_search_array(nums: &[i32], target: i32) -> i32 {
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    // 遍历数组
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    for (i, num) in nums.iter().enumerate() {
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        // 找到目标元素,返回其索引
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        if num == &target {
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            return i as i32;
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        }
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    }
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    // 未找到目标元素,返回 -1
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    return -1;
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}
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/* 线性查找(链表) */
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fn linear_search_linked_list(head: Rc<RefCell<ListNode<i32>>>, target: i32) -> Option<Rc<RefCell<ListNode<i32>>>> {
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    // 找到目标节点,返回之
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    if head.borrow().val == target {return Some(head)};
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    // 找到目标节点,返回之
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    if let Some(node) = &head.borrow_mut().next {
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        return linear_search_linked_list(node.clone(), target);
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    }
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    // 未找到目标节点,返回 None
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    return None;
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}
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/* Driver Code */
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pub fn main() {
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    let target = 3;
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    /* 在数组中执行线性查找 */
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    let nums = [ 1, 5, 3, 2, 4, 7, 5, 9, 10, 8 ];
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    let index = linear_search_array(&nums, target);
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    println!("目标元素 3 的索引 = {}", index);
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    /* 在链表中执行线性查找 */
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    let head = ListNode::arr_to_linked_list(&nums);
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    let node = linear_search_linked_list(head.unwrap(), target);
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    println!("目标节点值 3 的对应节点对象为 {:?}", node);
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}
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