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	abf1f115bf
	
	
	
		
			
			* A bug fixes * Sync zh and zh-hant versions. * Fix a question in chapter_array_and_linkedlist/summary.md * Optimize a definition in what_is_dsa.md * Fix the Contributing guidelines for Chinese-to-English. * Add a q&a in chapter_array_and_linkedlist/summary.md * Sync zh and zh-hant versions. * Update .gitignore * Sync zh and zh-hant versions.
		
			
				
	
	
		
			138 lines
		
	
	
		
			3.5 KiB
		
	
	
	
		
			C++
		
	
	
	
	
	
			
		
		
	
	
			138 lines
		
	
	
		
			3.5 KiB
		
	
	
	
		
			C++
		
	
	
	
	
	
| /**
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|  * File: array_binary_tree.cpp
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|  * Created Time: 2023-07-19
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|  * Author: krahets (krahets@163.com)
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|  */
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| 
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| #include "../utils/common.hpp"
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| 
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| /* 陣列表示下的二元樹類別 */
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| class ArrayBinaryTree {
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|   public:
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|     /* 建構子 */
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|     ArrayBinaryTree(vector<int> arr) {
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|         tree = arr;
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|     }
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| 
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|     /* 串列容量 */
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|     int size() {
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|         return tree.size();
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|     }
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| 
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|     /* 獲取索引為 i 節點的值 */
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|     int val(int i) {
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|         // 若索引越界,則返回 INT_MAX ,代表空位
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|         if (i < 0 || i >= size())
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|             return INT_MAX;
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|         return tree[i];
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|     }
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| 
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|     /* 獲取索引為 i 節點的左子節點的索引 */
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|     int left(int i) {
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|         return 2 * i + 1;
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|     }
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| 
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|     /* 獲取索引為 i 節點的右子節點的索引 */
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|     int right(int i) {
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|         return 2 * i + 2;
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|     }
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| 
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|     /* 獲取索引為 i 節點的父節點的索引 */
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|     int parent(int i) {
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|         return (i - 1) / 2;
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|     }
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| 
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|     /* 層序走訪 */
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|     vector<int> levelOrder() {
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|         vector<int> res;
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|         // 直接走訪陣列
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|         for (int i = 0; i < size(); i++) {
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|             if (val(i) != INT_MAX)
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|                 res.push_back(val(i));
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|         }
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|         return res;
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|     }
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| 
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|     /* 前序走訪 */
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|     vector<int> preOrder() {
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|         vector<int> res;
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|         dfs(0, "pre", res);
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|         return res;
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|     }
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| 
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|     /* 中序走訪 */
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|     vector<int> inOrder() {
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|         vector<int> res;
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|         dfs(0, "in", res);
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|         return res;
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|     }
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| 
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|     /* 後序走訪 */
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|     vector<int> postOrder() {
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|         vector<int> res;
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|         dfs(0, "post", res);
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|         return res;
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|     }
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| 
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|   private:
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|     vector<int> tree;
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| 
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|     /* 深度優先走訪 */
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|     void dfs(int i, string order, vector<int> &res) {
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|         // 若為空位,則返回
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|         if (val(i) == INT_MAX)
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|             return;
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|         // 前序走訪
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|         if (order == "pre")
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|             res.push_back(val(i));
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|         dfs(left(i), order, res);
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|         // 中序走訪
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|         if (order == "in")
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|             res.push_back(val(i));
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|         dfs(right(i), order, res);
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|         // 後序走訪
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|         if (order == "post")
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|             res.push_back(val(i));
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|     }
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| };
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| 
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| /* Driver Code */
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| int main() {
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|     // 初始化二元樹
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|     // 使用 INT_MAX 代表空位 nullptr
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|     vector<int> arr = {1, 2, 3, 4, INT_MAX, 6, 7, 8, 9, INT_MAX, INT_MAX, 12, INT_MAX, INT_MAX, 15};
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|     TreeNode *root = vectorToTree(arr);
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|     cout << "\n初始化二元樹\n";
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|     cout << "二元樹的陣列表示:\n";
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|     printVector(arr);
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|     cout << "二元樹的鏈結串列表示:\n";
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|     printTree(root);
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| 
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|     // 陣列表示下的二元樹類別
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|     ArrayBinaryTree abt(arr);
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| 
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|     // 訪問節點
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|     int i = 1;
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|     int l = abt.left(i), r = abt.right(i), p = abt.parent(i);
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|     cout << "\n當前節點的索引為 " << i << ",值為 " << abt.val(i) << "\n";
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|     cout << "其左子節點的索引為 " << l << ",值為 " << (abt.val(l) != INT_MAX ? to_string(abt.val(l)) : "nullptr") << "\n";
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|     cout << "其右子節點的索引為 " << r << ",值為 " << (abt.val(r) != INT_MAX ? to_string(abt.val(r)) : "nullptr") << "\n";
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|     cout << "其父節點的索引為 " << p << ",值為 " << (abt.val(p) != INT_MAX ? to_string(abt.val(p)) : "nullptr") << "\n";
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| 
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|     // 走訪樹
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|     vector<int> res = abt.levelOrder();
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|     cout << "\n層序走訪為: ";
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|     printVector(res);
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|     res = abt.preOrder();
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|     cout << "前序走訪為: ";
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|     printVector(res);
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|     res = abt.inOrder();
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|     cout << "中序走訪為: ";
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|     printVector(res);
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|     res = abt.postOrder();
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|     cout << "後序走訪為: ";
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|     printVector(res);
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| 
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|     return 0;
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| }
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