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			66 lines
		
	
	
		
			1.6 KiB
		
	
	
	
		
			Ruby
		
	
	
	
	
	
			
		
		
	
	
			66 lines
		
	
	
		
			1.6 KiB
		
	
	
	
		
			Ruby
		
	
	
	
	
	
| =begin
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| File: coin_change.rb
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| Created Time: 2024-05-29
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| Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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| =end
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| 
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| ### 零钱兑换:动态规划 ###
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| def coin_change_dp(coins, amt)
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|   n = coins.length
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|   _MAX = amt + 1
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|   # 初始化 dp 表
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|   dp = Array.new(n + 1) { Array.new(amt + 1, 0) }
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|   # 状态转移:首行首列
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|   (1...(amt + 1)).each { |a| dp[0][a] = _MAX }
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|   # 状态转移:其余行和列
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|   for i in 1...(n + 1)
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|     for a in 1...(amt + 1)
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|       if coins[i - 1] > a
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|         # 若超过目标金额,则不选硬币 i
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|         dp[i][a] = dp[i - 1][a]
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|       else
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|         # 不选和选硬币 i 这两种方案的较小值
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|         dp[i][a] = [dp[i - 1][a], dp[i][a - coins[i - 1]] + 1].min
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|       end
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|     end
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|   end
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|   dp[n][amt] != _MAX ? dp[n][amt] : -1
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| end
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| 
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| ### 零钱兑换:空间优化后的动态规划 ###
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| def coin_change_dp_comp(coins, amt)
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|   n = coins.length
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|   _MAX = amt + 1
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|   # 初始化 dp 表
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|   dp = Array.new(amt + 1, _MAX)
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|   dp[0] = 0
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|   # 状态转移
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|   for i in 1...(n + 1)
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|     # 正序遍历
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|     for a in 1...(amt + 1)
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|       if coins[i - 1] > a
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|         # 若超过目标金额,则不选硬币 i
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|         dp[a] = dp[a]
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|       else
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|         # 不选和选硬币 i 这两种方案的较小值
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|         dp[a] = [dp[a], dp[a - coins[i - 1]] + 1].min
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|       end
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|     end
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|   end
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|   dp[amt] != _MAX ? dp[amt] : -1
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| end
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| 
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| ### Driver Code ###
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| if __FILE__ == $0
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|   coins = [1, 2, 5]
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|   amt = 4
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| 
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|   # 动态规划
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|   res = coin_change_dp(coins, amt)
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|   puts "凑到目标金额所需的最少硬币数量为 #{res}"
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| 
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|   # 空间优化后的动态规划
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|   res = coin_change_dp_comp(coins, amt)
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|   puts "凑到目标金额所需的最少硬币数量为 #{res}"
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| end
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