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			80 lines
		
	
	
		
			2.2 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			80 lines
		
	
	
		
			2.2 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
/**
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 * File: permutations_i.c
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 * Created Time: 2023-06-04
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 * Author: Gonglja (glj0@outlook.com), krahets (krahets@163.com)
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 */
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#include "../utils/common.h"
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// 假设最多有 1000 个排列
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#define MAX_SIZE 1000
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/* 回溯算法:全排列 I */
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void backtrack(int *state, int stateSize, int *choices, int choicesSize, bool *selected, int **res, int *resSize) {
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    // 当状态长度等于元素数量时,记录解
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    if (stateSize == choicesSize) {
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        res[*resSize] = (int *)malloc(choicesSize * sizeof(int));
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        for (int i = 0; i < choicesSize; i++) {
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            res[*resSize][i] = state[i];
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        }
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        (*resSize)++;
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        return;
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    }
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    // 遍历所有选择
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    for (int i = 0; i < choicesSize; i++) {
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        int choice = choices[i];
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        // 剪枝:不允许重复选择元素
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        if (!selected[i]) {
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            // 尝试:做出选择,更新状态
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            selected[i] = true;
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            state[stateSize] = choice;
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            // 进行下一轮选择
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            backtrack(state, stateSize + 1, choices, choicesSize, selected, res, resSize);
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            // 回退:撤销选择,恢复到之前的状态
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            selected[i] = false;
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        }
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    }
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}
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/* 全排列 I */
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int **permutationsI(int *nums, int numsSize, int *returnSize) {
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    int *state = (int *)malloc(numsSize * sizeof(int));
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    bool *selected = (bool *)malloc(numsSize * sizeof(bool));
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    for (int i = 0; i < numsSize; i++) {
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        selected[i] = false;
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    }
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    int **res = (int **)malloc(MAX_SIZE * sizeof(int *));
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    *returnSize = 0;
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    backtrack(state, 0, nums, numsSize, selected, res, returnSize);
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    free(state);
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    free(selected);
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    return res;
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}
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/* Driver Code */
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int main() {
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    int nums[] = {1, 2, 3};
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    int numsSize = sizeof(nums) / sizeof(nums[0]);
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    int returnSize;
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    int **res = permutationsI(nums, numsSize, &returnSize);
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    printf("输入数组 nums = ");
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    printArray(nums, numsSize);
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    printf("\n所有排列 res = \n");
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    for (int i = 0; i < returnSize; i++) {
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        printArray(res[i], numsSize);
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    }
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    // 释放内存
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    for (int i = 0; i < returnSize; i++) {
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        free(res[i]);
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    }
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    free(res);
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    return 0;
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}
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