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			141 lines
		
	
	
		
			3.8 KiB
		
	
	
	
		
			JavaScript
		
	
	
	
	
	
			
		
		
	
	
			141 lines
		
	
	
		
			3.8 KiB
		
	
	
	
		
			JavaScript
		
	
	
	
	
	
/**
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 * File: binary_search_tree.js
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 * Created Time: 2022-12-04
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 * Author: IsChristina (christinaxia77@foxmail.com)
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 */
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const { TreeNode } = require('../modules/TreeNode');
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const { printTree } = require('../modules/PrintUtil');
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/* 二叉搜索树 */
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let root;
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function BinarySearchTree(nums) {
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    nums.sort((a, b) => {
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        return a - b;
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    }); // 排序数组
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    root = buildTree(nums, 0, nums.length - 1); // 构建二叉搜索树
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}
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/* 获取二叉树根节点 */
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function getRoot() {
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    return root;
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}
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/* 构建二叉搜索树 */
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function buildTree(nums, i, j) {
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    if (i > j) return null;
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    // 将数组中间节点作为根节点
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    let mid = Math.floor((i + j) / 2);
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    let root = new TreeNode(nums[mid]);
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    // 递归建立左子树和右子树
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    root.left = buildTree(nums, i, mid - 1);
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    root.right = buildTree(nums, mid + 1, j);
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    return root;
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}
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/* 查找节点 */
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function search(num) {
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    let cur = root;
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    // 循环查找,越过叶节点后跳出
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    while (cur !== null) {
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        // 目标节点在 cur 的右子树中
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        if (cur.val < num) cur = cur.right;
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        // 目标节点在 cur 的左子树中
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        else if (cur.val > num) cur = cur.left;
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        // 找到目标节点,跳出循环
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        else break;
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    }
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    // 返回目标节点
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    return cur;
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}
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/* 插入节点 */
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function insert(num) {
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    // 若树为空,直接提前返回
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    if (root === null) return;
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    let cur = root,
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        pre = null;
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    // 循环查找,越过叶节点后跳出
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    while (cur !== null) {
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        // 找到重复节点,直接返回
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        if (cur.val === num) return;
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        pre = cur;
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        // 插入位置在 cur 的右子树中
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        if (cur.val < num) cur = cur.right;
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        // 插入位置在 cur 的左子树中
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        else cur = cur.left;
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    }
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    // 插入节点
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    let node = new TreeNode(num);
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    if (pre.val < num) pre.right = node;
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    else pre.left = node;
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}
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/* 删除节点 */
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function remove(num) {
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    // 若树为空,直接提前返回
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    if (root === null) return;
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    let cur = root,
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        pre = null;
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    // 循环查找,越过叶节点后跳出
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    while (cur !== null) {
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        // 找到待删除节点,跳出循环
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        if (cur.val === num) break;
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        pre = cur;
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        // 待删除节点在 cur 的右子树中
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        if (cur.val < num) cur = cur.right;
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        // 待删除节点在 cur 的左子树中
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        else cur = cur.left;
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    }
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    // 若无待删除节点,则直接返回
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    if (cur === null) return;
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    // 子节点数量 = 0 or 1
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    if (cur.left === null || cur.right === null) {
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        // 当子节点数量 = 0 / 1 时, child = null / 该子节点
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        let child = cur.left !== null ? cur.left : cur.right;
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        // 删除节点 cur
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        if (pre.left === cur) pre.left = child;
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        else pre.right = child;
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    }
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    // 子节点数量 = 2
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    else {
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        // 获取中序遍历中 cur 的下一个节点
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        let tmp = cur.right;
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        while (tmp.left !== null) {
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            tmp = tmp.left;
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        }
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        // 递归删除节点 tmp
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        remove(tmp.val);
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        // 用 tmp 覆盖 cur
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        cur.val = tmp.val;
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    }
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}
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/* Driver Code */
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/* 初始化二叉搜索树 */
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const nums = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15];
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BinarySearchTree(nums);
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console.log('\n初始化的二叉树为\n');
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printTree(getRoot());
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/* 查找节点 */
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let node = search(7);
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console.log('\n查找到的节点对象为 ' + node + ',节点值 = ' + node.val);
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/* 插入节点 */
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insert(16);
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console.log('\n插入节点 16 后,二叉树为\n');
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printTree(getRoot());
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/* 删除节点 */
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remove(1);
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console.log('\n删除节点 1 后,二叉树为\n');
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printTree(getRoot());
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remove(2);
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console.log('\n删除节点 2 后,二叉树为\n');
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printTree(getRoot());
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remove(4);
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console.log('\n删除节点 4 后,二叉树为\n');
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printTree(getRoot());
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