mirror of
				https://github.com/krahets/hello-algo.git
				synced 2025-11-04 22:28:40 +08:00 
			
		
		
		
	
		
			
				
	
	
		
			71 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Ruby
		
	
	
	
	
	
			
		
		
	
	
			71 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Ruby
		
	
	
	
	
	
=begin
 | 
						|
File: recursion.rb
 | 
						|
Created Time: 2024-03-30
 | 
						|
Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
 | 
						|
=end
 | 
						|
 | 
						|
### 递归 ###
 | 
						|
def recur(n)
 | 
						|
  # 终止条件
 | 
						|
  return 1 if n == 1
 | 
						|
  # 递:递归调用
 | 
						|
  res = recur(n - 1)
 | 
						|
  # 归:返回结果
 | 
						|
  n + res
 | 
						|
end
 | 
						|
 | 
						|
### 使用迭代模拟递归 ###
 | 
						|
def for_loop_recur(n)
 | 
						|
  # 使用一个显式的栈来模拟系统调用栈
 | 
						|
  stack = []
 | 
						|
  res = 0
 | 
						|
 | 
						|
  # 递:递归调用
 | 
						|
  for i in n.downto(0)
 | 
						|
    # 通过“入栈操作”模拟“递”
 | 
						|
    stack << i
 | 
						|
  end
 | 
						|
  # 归:返回结果
 | 
						|
  while !stack.empty?
 | 
						|
    res += stack.pop
 | 
						|
  end
 | 
						|
 | 
						|
  # res = 1+2+3+...+n
 | 
						|
  res
 | 
						|
end
 | 
						|
 | 
						|
### 尾递归 ###
 | 
						|
def tail_recur(n, res)
 | 
						|
  # 终止条件
 | 
						|
  return res if n == 0
 | 
						|
  # 尾递归调用
 | 
						|
  tail_recur(n - 1, res + n)
 | 
						|
end
 | 
						|
 | 
						|
### 斐波那契数列:递归 ###
 | 
						|
def fib(n)
 | 
						|
  # 终止条件 f(1) = 0, f(2) = 1
 | 
						|
  return n - 1 if n == 1 || n == 2
 | 
						|
  # 递归调用 f(n) = f(n-1) + f(n-2)
 | 
						|
  res = fib(n - 1) + fib(n - 2)
 | 
						|
  # 返回结果 f(n)
 | 
						|
  res
 | 
						|
end
 | 
						|
 | 
						|
### Driver Code ###
 | 
						|
if __FILE__ == $0
 | 
						|
  n = 5
 | 
						|
 | 
						|
  res = recur(n)
 | 
						|
  puts "\n递归函数的求和结果 res = #{res}"
 | 
						|
 | 
						|
  res = for_loop_recur(n)
 | 
						|
  puts "\n使用迭代模拟递归求和结果 res = #{res}"
 | 
						|
 | 
						|
  res = tail_recur(n, 0)
 | 
						|
  puts "\n尾递归函数的求和结果 res = #{res}"
 | 
						|
 | 
						|
  res = fib(n)
 | 
						|
  puts "\n斐波那契数列的第 #{n} 项为 #{res}"
 | 
						|
end
 |