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			167 lines
		
	
	
		
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			167 lines
		
	
	
		
			3.5 KiB
		
	
	
	
		
			Go
		
	
	
	
	
	
// File: binary_search_tree.go
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// Created Time: 2022-11-26
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// Author: Reanon (793584285@qq.com)
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package chapter_tree
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import (
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	"sort"
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	. "github.com/krahets/hello-algo/pkg"
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)
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type binarySearchTree struct {
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	root *TreeNode
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}
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func newBinarySearchTree(nums []int) *binarySearchTree {
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	// sorting array
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	sort.Ints(nums)
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	root := buildBinarySearchTree(nums, 0, len(nums)-1)
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	return &binarySearchTree{
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		root: root,
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	}
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}
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/* 获取根结点 */
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func (bst *binarySearchTree) getRoot() *TreeNode {
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	return bst.root
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}
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/* 获取中序遍历的下一个结点(仅适用于 root 有左子结点的情况) */
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func (bst *binarySearchTree) getInOrderNext(node *TreeNode) *TreeNode {
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	if node == nil {
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		return node
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	}
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	// 循环访问左子结点,直到叶结点时为最小结点,跳出
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	for node.Left != nil {
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		node = node.Left
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	}
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	return node
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}
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/* 查找结点 */
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func (bst *binarySearchTree) search(num int) *TreeNode {
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	node := bst.root
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	// 循环查找,越过叶结点后跳出
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	for node != nil {
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		if node.Val < num {
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			// 目标结点在 cur 的右子树中
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			node = node.Right
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		} else if node.Val > num {
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			// 目标结点在 cur 的左子树中
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			node = node.Left
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		} else {
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			// 找到目标结点,跳出循环
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			break
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		}
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	}
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	// 返回目标结点
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	return node
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}
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/* 插入结点 */
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func (bst *binarySearchTree) insert(num int) *TreeNode {
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	cur := bst.root
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	// 若树为空,直接提前返回
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	if cur == nil {
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		return nil
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	}
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	// 待插入结点之前的结点位置
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	var prev *TreeNode = nil
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	// 循环查找,越过叶结点后跳出
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	for cur != nil {
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		if cur.Val == num {
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			return nil
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		}
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		prev = cur
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		if cur.Val < num {
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			cur = cur.Right
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		} else {
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			cur = cur.Left
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		}
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	}
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	// 插入结点
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	node := NewTreeNode(num)
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	if prev.Val < num {
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		prev.Right = node
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	} else {
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		prev.Left = node
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	}
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	return cur
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}
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/* 删除结点 */
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func (bst *binarySearchTree) remove(num int) *TreeNode {
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	cur := bst.root
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	// 若树为空,直接提前返回
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	if cur == nil {
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		return nil
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	}
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	// 待删除结点之前的结点位置
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	var prev *TreeNode = nil
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	// 循环查找,越过叶结点后跳出
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	for cur != nil {
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		if cur.Val == num {
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			break
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		}
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		prev = cur
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		if cur.Val < num {
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			// 待删除结点在右子树中
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			cur = cur.Right
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		} else {
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			// 待删除结点在左子树中
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			cur = cur.Left
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		}
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	}
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	// 若无待删除结点,则直接返回
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	if cur == nil {
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		return nil
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	}
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	// 子结点数为 0 或 1
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	if cur.Left == nil || cur.Right == nil {
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		var child *TreeNode = nil
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		// 取出待删除结点的子结点
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		if cur.Left != nil {
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			child = cur.Left
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		} else {
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			child = cur.Right
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		}
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		// 将子结点替换为待删除结点
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		if prev.Left == cur {
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			prev.Left = child
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		} else {
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			prev.Right = child
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		}
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		// 子结点数为 2
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	} else {
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		// 获取中序遍历中待删除结点 cur 的下一个结点
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		next := bst.getInOrderNext(cur)
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		temp := next.Val
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		// 递归删除结点 next
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		bst.remove(next.Val)
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		// 将 next 的值复制给 cur
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		cur.Val = temp
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	}
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	return cur
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}
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// buildBinarySearchTree Build a binary search tree from array.
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func buildBinarySearchTree(nums []int, left, right int) *TreeNode {
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	if left > right {
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		return nil
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	}
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	// 将数组中间结点作为根结点
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	middle := left + (right-left)>>1
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	root := NewTreeNode(nums[middle])
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	// 递归构建左子树和右子树
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	root.Left = buildBinarySearchTree(nums, left, middle-1)
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	root.Right = buildBinarySearchTree(nums, middle+1, right)
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	return root
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}
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// print binary search tree
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func (bst *binarySearchTree) print() {
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	PrintTree(bst.root)
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}
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