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* Add the intial translation of code of all the languages * test * revert * Remove * Add Python and Java code for EN version
70 lines
2.1 KiB
Python
70 lines
2.1 KiB
Python
"""
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File: tree_node.py
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Created Time: 2021-12-11
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Author: krahets (krahets@163.com)
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"""
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from collections import deque
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class TreeNode:
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"""Binary tree node class"""
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def __init__(self, val: int = 0):
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self.val: int = val # Node value
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self.height: int = 0 # Node height
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self.left: TreeNode | None = None # Reference to the left child node
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self.right: TreeNode | None = None # Reference to the right child node
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# For serialization encoding rules, refer to:
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# https://www.hello-algo.com/chapter_tree/array_representation_of_tree/
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# Array representation of the binary tree:
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# [1, 2, 3, 4, None, 6, 7, 8, 9, None, None, 12, None, None, 15]
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# Linked list representation of the binary tree:
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# /——— 15
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# /——— 7
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# /——— 3
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# | \——— 6
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# | \——— 12
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# ——— 1
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# \——— 2
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# | /——— 9
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# \——— 4
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# \——— 8
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def list_to_tree_dfs(arr: list[int], i: int) -> TreeNode | None:
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"""Deserialize a list into a binary tree: Recursively"""
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# If the index is out of array bounds, or the corresponding element is None, return None
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if i < 0 or i >= len(arr) or arr[i] is None:
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return None
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# Construct the current node
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root = TreeNode(arr[i])
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# Recursively construct left and right subtrees
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root.left = list_to_tree_dfs(arr, 2 * i + 1)
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root.right = list_to_tree_dfs(arr, 2 * i + 2)
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return root
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def list_to_tree(arr: list[int]) -> TreeNode | None:
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"""Deserialize a list into a binary tree"""
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return list_to_tree_dfs(arr, 0)
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def tree_to_list_dfs(root: TreeNode, i: int, res: list[int]) -> list[int]:
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"""Serialize a binary tree into a list: Recursively"""
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if root is None:
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return
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if i >= len(res):
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res += [None] * (i - len(res) + 1)
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res[i] = root.val
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tree_to_list_dfs(root.left, 2 * i + 1, res)
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tree_to_list_dfs(root.right, 2 * i + 2, res)
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def tree_to_list(root: TreeNode | None) -> list[int]:
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"""Serialize a binary tree into a list"""
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res = []
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tree_to_list_dfs(root, 0, res)
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return res
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