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	1c0f350ad6
	
	
	
		
			
			* Add the intial translation of code of all the languages * test * revert * Remove * Add Python and Java code for EN version
		
			
				
	
	
		
			91 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
			
		
		
	
	
			91 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
| """
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| File: space_complexity.py
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| Created Time: 2022-11-25
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| Author: krahets (krahets@163.com)
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| """
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| 
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| import sys
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| from pathlib import Path
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| 
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| sys.path.append(str(Path(__file__).parent.parent))
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| from modules import ListNode, TreeNode, print_tree
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| 
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| 
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| def function() -> int:
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|     """Function"""
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|     # Perform some operations
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|     return 0
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| 
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| 
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| def constant(n: int):
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|     """Constant complexity"""
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|     # Constants, variables, objects occupy O(1) space
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|     a = 0
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|     nums = [0] * 10000
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|     node = ListNode(0)
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|     # Variables in a loop occupy O(1) space
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|     for _ in range(n):
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|         c = 0
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|     # Functions in a loop occupy O(1) space
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|     for _ in range(n):
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|         function()
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| 
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| 
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| def linear(n: int):
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|     """Linear complexity"""
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|     # A list of length n occupies O(n) space
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|     nums = [0] * n
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|     # A hash table of length n occupies O(n) space
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|     hmap = dict[int, str]()
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|     for i in range(n):
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|         hmap[i] = str(i)
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| 
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| 
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| def linear_recur(n: int):
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|     """Linear complexity (recursive implementation)"""
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|     print("Recursive n =", n)
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|     if n == 1:
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|         return
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|     linear_recur(n - 1)
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| 
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| 
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| def quadratic(n: int):
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|     """Quadratic complexity"""
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|     # A two-dimensional list occupies O(n^2) space
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|     num_matrix = [[0] * n for _ in range(n)]
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| 
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| 
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| def quadratic_recur(n: int) -> int:
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|     """Quadratic complexity (recursive implementation)"""
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|     if n <= 0:
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|         return 0
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|     # Array nums length = n, n-1, ..., 2, 1
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|     nums = [0] * n
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|     return quadratic_recur(n - 1)
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| 
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| 
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| def build_tree(n: int) -> TreeNode | None:
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|     """Exponential complexity (building a full binary tree)"""
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|     if n == 0:
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|         return None
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|     root = TreeNode(0)
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|     root.left = build_tree(n - 1)
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|     root.right = build_tree(n - 1)
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|     return root
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| 
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| 
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| """Driver Code"""
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| if __name__ == "__main__":
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|     n = 5
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|     # Constant complexity
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|     constant(n)
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|     # Linear complexity
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|     linear(n)
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|     linear_recur(n)
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|     # Quadratic complexity
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|     quadratic(n)
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|     quadratic_recur(n)
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|     # Exponential complexity
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|     root = build_tree(n)
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|     print_tree(root)
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