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			56 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Dart
		
	
	
	
	
	
			
		
		
	
	
			56 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Dart
		
	
	
	
	
	
/**
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 * File: build_tree.dart
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 * Created Time: 2023-08-10
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 * Author: liuyuxin (gvenusleo@gmail.com)
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 */
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import '../utils/print_util.dart';
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import '../utils/tree_node.dart';
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/* 构建二叉树:分治 */
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TreeNode? dfs(
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  List<int> preorder,
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  Map<int, int> inorderMap,
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  int i,
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  int l,
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  int r,
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) {
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  // 子树区间为空时终止
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  if (r - l < 0) {
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    return null;
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  }
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  // 初始化根节点
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  TreeNode? root = TreeNode(preorder[i]);
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  // 查询 m ,从而划分左右子树
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  int m = inorderMap[preorder[i]]!;
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  // 子问题:构建左子树
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  root.left = dfs(preorder, inorderMap, i + 1, l, m - 1);
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  // 子问题:构建右子树
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  root.right = dfs(preorder, inorderMap, i + 1 + m - l, m + 1, r);
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  // 返回根节点
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  return root;
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}
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/* 构建二叉树 */
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TreeNode? buildTree(List<int> preorder, List<int> inorder) {
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  // 初始化哈希表,存储 inorder 元素到索引的映射
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  Map<int, int> inorderMap = {};
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  for (int i = 0; i < inorder.length; i++) {
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    inorderMap[inorder[i]] = i;
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  }
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  TreeNode? root = dfs(preorder, inorderMap, 0, 0, inorder.length - 1);
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  return root;
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}
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/* Driver Code */
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void main() {
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  List<int> preorder = [3, 9, 2, 1, 7];
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  List<int> inorder = [9, 3, 1, 2, 7];
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  print("前序遍历 = $preorder");
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  print("中序遍历 = $inorder");
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  TreeNode? root = buildTree(preorder, inorder);
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  print("构建的二叉树为:");
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  printTree(root!);
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}
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