mirror of
				https://github.com/krahets/hello-algo.git
				synced 2025-11-04 14:18:20 +08:00 
			
		
		
		
	* cargo fmt code * Add empty line to seperate unrelated comments * Fix review * Update bubble_sort.rs * Update merge_sort.rs --------- Co-authored-by: Yudong Jin <krahets@163.com>
		
			
				
	
	
		
			196 lines
		
	
	
		
			6.5 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
			
		
		
	
	
			196 lines
		
	
	
		
			6.5 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
/*
 | 
						|
 * File: binary_search_tree.rs
 | 
						|
 * Created Time: 2023-04-20
 | 
						|
 * Author: xBLACKICEx (xBLACKICE@outlook.com)、night-cruise (2586447362@qq.com)
 | 
						|
 */
 | 
						|
 | 
						|
include!("../include/include.rs");
 | 
						|
 | 
						|
use std::cell::RefCell;
 | 
						|
use std::cmp::Ordering;
 | 
						|
use std::rc::Rc;
 | 
						|
 | 
						|
use tree_node::TreeNode;
 | 
						|
 | 
						|
type OptionTreeNodeRc = Option<Rc<RefCell<TreeNode>>>;
 | 
						|
 | 
						|
/* 二叉搜索树 */
 | 
						|
pub struct BinarySearchTree {
 | 
						|
    root: OptionTreeNodeRc,
 | 
						|
}
 | 
						|
 | 
						|
impl BinarySearchTree {
 | 
						|
    /* 构造方法 */
 | 
						|
    pub fn new() -> Self {
 | 
						|
        // 初始化空树
 | 
						|
        Self { root: None }
 | 
						|
    }
 | 
						|
 | 
						|
    /* 获取二叉树根节点 */
 | 
						|
    pub fn get_root(&self) -> OptionTreeNodeRc {
 | 
						|
        self.root.clone()
 | 
						|
    }
 | 
						|
 | 
						|
    /* 查找节点 */
 | 
						|
    pub fn search(&self, num: i32) -> OptionTreeNodeRc {
 | 
						|
        let mut cur = self.root.clone();
 | 
						|
        // 循环查找,越过叶节点后跳出
 | 
						|
        while let Some(node) = cur.clone() {
 | 
						|
            match num.cmp(&node.borrow().val) {
 | 
						|
                // 目标节点在 cur 的右子树中
 | 
						|
                Ordering::Greater => cur = node.borrow().right.clone(),
 | 
						|
                // 目标节点在 cur 的左子树中
 | 
						|
                Ordering::Less => cur = node.borrow().left.clone(),
 | 
						|
                // 找到目标节点,跳出循环
 | 
						|
                Ordering::Equal => break,
 | 
						|
            }
 | 
						|
        }
 | 
						|
 | 
						|
        // 返回目标节点
 | 
						|
        cur
 | 
						|
    }
 | 
						|
 | 
						|
    /* 插入节点 */
 | 
						|
    pub fn insert(&mut self, num: i32) {
 | 
						|
        // 若树为空,则初始化根节点
 | 
						|
        if self.root.is_none() {
 | 
						|
            self.root = Some(TreeNode::new(num));
 | 
						|
            return;
 | 
						|
        }
 | 
						|
        let mut cur = self.root.clone();
 | 
						|
        let mut pre = None;
 | 
						|
        // 循环查找,越过叶节点后跳出
 | 
						|
        while let Some(node) = cur.clone() {
 | 
						|
            match num.cmp(&node.borrow().val) {
 | 
						|
                // 找到重复节点,直接返回
 | 
						|
                Ordering::Equal => return,
 | 
						|
                // 插入位置在 cur 的右子树中
 | 
						|
                Ordering::Greater => {
 | 
						|
                    pre = cur.clone();
 | 
						|
                    cur = node.borrow().right.clone();
 | 
						|
                }
 | 
						|
                // 插入位置在 cur 的左子树中
 | 
						|
                Ordering::Less => {
 | 
						|
                    pre = cur.clone();
 | 
						|
                    cur = node.borrow().left.clone();
 | 
						|
                }
 | 
						|
            }
 | 
						|
        }
 | 
						|
        // 插入节点
 | 
						|
        let pre = pre.unwrap();
 | 
						|
        let node = Some(TreeNode::new(num));
 | 
						|
        if num > pre.borrow().val {
 | 
						|
            pre.borrow_mut().right = node;
 | 
						|
        } else {
 | 
						|
            pre.borrow_mut().left = node;
 | 
						|
        }
 | 
						|
    }
 | 
						|
 | 
						|
    /* 删除节点 */
 | 
						|
    pub fn remove(&mut self, num: i32) {
 | 
						|
        // 若树为空,直接提前返回
 | 
						|
        if self.root.is_none() {
 | 
						|
            return;
 | 
						|
        }
 | 
						|
        let mut cur = self.root.clone();
 | 
						|
        let mut pre = None;
 | 
						|
        // 循环查找,越过叶节点后跳出
 | 
						|
        while let Some(node) = cur.clone() {
 | 
						|
            match num.cmp(&node.borrow().val) {
 | 
						|
                // 找到待删除节点,跳出循环
 | 
						|
                Ordering::Equal => break,
 | 
						|
                // 待删除节点在 cur 的右子树中
 | 
						|
                Ordering::Greater => {
 | 
						|
                    pre = cur.clone();
 | 
						|
                    cur = node.borrow().right.clone();
 | 
						|
                }
 | 
						|
                // 待删除节点在 cur 的左子树中
 | 
						|
                Ordering::Less => {
 | 
						|
                    pre = cur.clone();
 | 
						|
                    cur = node.borrow().left.clone();
 | 
						|
                }
 | 
						|
            }
 | 
						|
        }
 | 
						|
        // 若无待删除节点,则直接返回
 | 
						|
        if cur.is_none() {
 | 
						|
            return;
 | 
						|
        }
 | 
						|
        let cur = cur.unwrap();
 | 
						|
        let (left_child, right_child) = (cur.borrow().left.clone(), cur.borrow().right.clone());
 | 
						|
        match (left_child.clone(), right_child.clone()) {
 | 
						|
            // 子节点数量 = 0 or 1
 | 
						|
            (None, None) | (Some(_), None) | (None, Some(_)) => {
 | 
						|
                // 当子节点数量 = 0 / 1 时, child = nullptr / 该子节点
 | 
						|
                let child = left_child.or(right_child);
 | 
						|
                let pre = pre.unwrap();
 | 
						|
                // 删除节点 cur
 | 
						|
                if !Rc::ptr_eq(&cur, self.root.as_ref().unwrap()) {
 | 
						|
                    let left = pre.borrow().left.clone();
 | 
						|
                    if left.is_some() && Rc::ptr_eq(&left.as_ref().unwrap(), &cur) {
 | 
						|
                        pre.borrow_mut().left = child;
 | 
						|
                    } else {
 | 
						|
                        pre.borrow_mut().right = child;
 | 
						|
                    }
 | 
						|
                } else {
 | 
						|
                    // 若删除节点为根节点,则重新指定根节点
 | 
						|
                    self.root = child;
 | 
						|
                }
 | 
						|
            }
 | 
						|
            // 子节点数量 = 2
 | 
						|
            (Some(_), Some(_)) => {
 | 
						|
                // 获取中序遍历中 cur 的下一个节点
 | 
						|
                let mut tmp = cur.borrow().right.clone();
 | 
						|
                while let Some(node) = tmp.clone() {
 | 
						|
                    if node.borrow().left.is_some() {
 | 
						|
                        tmp = node.borrow().left.clone();
 | 
						|
                    } else {
 | 
						|
                        break;
 | 
						|
                    }
 | 
						|
                }
 | 
						|
                let tmpval = tmp.unwrap().borrow().val;
 | 
						|
                // 递归删除节点 tmp
 | 
						|
                self.remove(tmpval);
 | 
						|
                // 用 tmp 覆盖 cur
 | 
						|
                cur.borrow_mut().val = tmpval;
 | 
						|
            }
 | 
						|
        }
 | 
						|
    }
 | 
						|
}
 | 
						|
 | 
						|
/* Driver Code */
 | 
						|
fn main() {
 | 
						|
    /* 初始化二叉搜索树 */
 | 
						|
    let mut bst = BinarySearchTree::new();
 | 
						|
    // 请注意,不同的插入顺序会生成不同的二叉树,该序列可以生成一个完美二叉树
 | 
						|
    let nums = [8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15];
 | 
						|
    for &num in &nums {
 | 
						|
        bst.insert(num);
 | 
						|
    }
 | 
						|
    println!("\n初始化的二叉树为\n");
 | 
						|
    print_util::print_tree(bst.get_root().as_ref().unwrap());
 | 
						|
 | 
						|
    /* 查找结点 */
 | 
						|
    let node = bst.search(7);
 | 
						|
    println!(
 | 
						|
        "\n查找到的节点对象为 {:?},节点值 = {}",
 | 
						|
        node.clone().unwrap(),
 | 
						|
        node.clone().unwrap().borrow().val
 | 
						|
    );
 | 
						|
 | 
						|
    /* 插入节点 */
 | 
						|
    bst.insert(16);
 | 
						|
    println!("\n插入节点 16 后,二叉树为\n");
 | 
						|
    print_util::print_tree(bst.get_root().as_ref().unwrap());
 | 
						|
 | 
						|
    /* 删除节点 */
 | 
						|
    bst.remove(1);
 | 
						|
    println!("\n删除节点 1 后,二叉树为\n");
 | 
						|
    print_util::print_tree(bst.get_root().as_ref().unwrap());
 | 
						|
    bst.remove(2);
 | 
						|
    println!("\n删除节点 2 后,二叉树为\n");
 | 
						|
    print_util::print_tree(bst.get_root().as_ref().unwrap());
 | 
						|
    bst.remove(4);
 | 
						|
    println!("\n删除节点 4 后,二叉树为\n");
 | 
						|
    print_util::print_tree(bst.get_root().as_ref().unwrap());
 | 
						|
}
 |