mirror of
				https://github.com/krahets/hello-algo.git
				synced 2025-11-04 06:07:20 +08:00 
			
		
		
		
	Use PascalCase for all structs in C. SImplify n_queens.c Format C code for chapter of graph.
		
			
				
	
	
		
			61 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			61 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
/**
 | 
						|
 * File: coin_change_greedy.c
 | 
						|
 * Created Time: 2023-09-07
 | 
						|
 * Author: lwbaptx (lwbaptx@gmail.com)
 | 
						|
 */
 | 
						|
 | 
						|
#include "../utils/common.h"
 | 
						|
 | 
						|
/* 零钱兑换:贪心 */
 | 
						|
int coinChangeGreedy(int *coins, int size, int amt) {
 | 
						|
    // 假设 coins 列表有序
 | 
						|
    int i = size - 1;
 | 
						|
    int count = 0;
 | 
						|
    // 循环进行贪心选择,直到无剩余金额
 | 
						|
    while (amt > 0) {
 | 
						|
        // 找到小于且最接近剩余金额的硬币
 | 
						|
        while (i > 0 && coins[i] > amt) {
 | 
						|
            i--;
 | 
						|
        }
 | 
						|
        // 选择 coins[i]
 | 
						|
        amt -= coins[i];
 | 
						|
        count++;
 | 
						|
    }
 | 
						|
    // 若未找到可行方案,则返回 -1
 | 
						|
    return amt == 0 ? count : -1;
 | 
						|
}
 | 
						|
 | 
						|
/* Driver Code */
 | 
						|
int main() {
 | 
						|
    // 贪心:能够保证找到全局最优解
 | 
						|
    int coins1[6] = {1, 5, 10, 20, 50, 100};
 | 
						|
    int amt = 186;
 | 
						|
    int res = coinChangeGreedy(coins1, 6, amt);
 | 
						|
    printf("\ncoins = ");
 | 
						|
    printArray(coins1, 6);
 | 
						|
    printf("amt = %d\n", amt);
 | 
						|
    printf("凑到 %d 所需的最少硬币数量为 %d\n", amt, res);
 | 
						|
 | 
						|
    // 贪心:无法保证找到全局最优解
 | 
						|
    int coins2[3] = {1, 20, 50};
 | 
						|
    amt = 60;
 | 
						|
    res = coinChangeGreedy(coins2, 3, amt);
 | 
						|
    printf("\ncoins = ");
 | 
						|
    printArray(coins2, 3);
 | 
						|
    printf("amt = %d\n", amt);
 | 
						|
    printf("凑到 %d 所需的最少硬币数量为 %d\n", amt, res);
 | 
						|
    printf("实际上需要的最少数量为 3 ,即 20 + 20 + 20\n");
 | 
						|
 | 
						|
    // 贪心:无法保证找到全局最优解
 | 
						|
    int coins3[3] = {1, 49, 50};
 | 
						|
    amt = 98;
 | 
						|
    res = coinChangeGreedy(coins3, 3, amt);
 | 
						|
    printf("\ncoins = ");
 | 
						|
    printArray(coins3, 3);
 | 
						|
    printf("amt = %d\n", amt);
 | 
						|
    printf("凑到 %d 所需的最少硬币数量为 %d\n", amt, res);
 | 
						|
    printf("实际上需要的最少数量为 2 ,即 49 + 49\n");
 | 
						|
 | 
						|
    return 0;
 | 
						|
}
 |