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			55 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
			
		
		
	
	
			55 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
"""
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File: build_tree.py
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Created Time: 2023-07-15
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Author: krahets (krahets@163.com)
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"""
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import sys
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from pathlib import Path
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sys.path.append(str(Path(__file__).parent.parent))
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from modules import TreeNode, print_tree
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def dfs(
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    preorder: list[int],
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    inorder_map: dict[int, int],
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    i: int,
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    l: int,
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    r: int,
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) -> TreeNode | None:
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    """构建二叉树:分治"""
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    # 子树区间为空时终止
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    if r - l < 0:
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        return None
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    # 初始化根节点
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    root = TreeNode(preorder[i])
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    # 查询 m ,从而划分左右子树
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    m = inorder_map[preorder[i]]
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    # 子问题:构建左子树
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    root.left = dfs(preorder, inorder_map, i + 1, l, m - 1)
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    # 子问题:构建右子树
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    root.right = dfs(preorder, inorder_map, i + 1 + m - l, m + 1, r)
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    # 返回根节点
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    return root
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def build_tree(preorder: list[int], inorder: list[int]) -> TreeNode | None:
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    """构建二叉树"""
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    # 初始化哈希表,存储 inorder 元素到索引的映射
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    inorder_map = {val: i for i, val in enumerate(inorder)}
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    root = dfs(preorder, inorder_map, 0, 0, len(inorder) - 1)
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    return root
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"""Driver Code"""
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if __name__ == "__main__":
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    preorder = [3, 9, 2, 1, 7]
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    inorder = [9, 3, 1, 2, 7]
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    print(f"前序遍历 = {preorder}")
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    print(f"中序遍历 = {inorder}")
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    root = build_tree(preorder, inorder)
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    print("构建的二叉树为:")
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    print_tree(root)
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