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			52 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			Java
		
	
	
	
	
	
			
		
		
	
	
			52 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			Java
		
	
	
	
	
	
/**
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 * File: build_tree.java
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 * Created Time: 2023-07-17
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 * Author: Krahets (krahets@163.com)
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 */
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package chapter_divide_and_conquer;
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import utils.*;
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import java.util.*;
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public class build_tree {
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    /* 构建二叉树:分治 */
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    static TreeNode dfs(int[] preorder, int[] inorder, Map<Integer, Integer> hmap, int i, int l, int r) {
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        // 子树区间为空时终止
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        if (r - l < 0)
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            return null;
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        // 初始化根节点
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        TreeNode root = new TreeNode(preorder[i]);
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        // 查询 m ,从而划分左右子树
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        int m = hmap.get(preorder[i]);
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        // 子问题:构建左子树
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        root.left = dfs(preorder, inorder, hmap, i + 1, l, m - 1);
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        // 子问题:构建右子树
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        root.right = dfs(preorder, inorder, hmap, i + 1 + m - l, m + 1, r);
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        // 返回根节点
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        return root;
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    }
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    /* 构建二叉树 */
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    static TreeNode buildTree(int[] preorder, int[] inorder) {
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        // 初始化哈希表,存储 inorder 元素到索引的映射
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        Map<Integer, Integer> hmap = new HashMap<>();
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        for (int i = 0; i < inorder.length; i++) {
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            hmap.put(inorder[i], i);
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        }
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        TreeNode root = dfs(preorder, inorder, hmap, 0, 0, inorder.length - 1);
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        return root;
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    }
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    public static void main(String[] args) {
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        int[] preorder = { 3, 9, 2, 1, 7 };
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        int[] inorder = { 9, 3, 1, 2, 7 };
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        System.out.println("前序遍历 = " + Arrays.toString(preorder));
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        System.out.println("中序遍历 = " + Arrays.toString(inorder));
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        TreeNode root = buildTree(preorder, inorder);
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        System.out.println("构建的二叉树为:");
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        PrintUtil.printTree(root);
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    }
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}
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