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			115 lines
		
	
	
		
			2.5 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
			
		
		
	
	
			115 lines
		
	
	
		
			2.5 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
/*
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 * File: space_complexity.rs
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 * Created Time: 2023-03-11
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 * Author: codingonion (coderonion@gmail.com)
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 */
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use hello_algo_rust::include::{print_util, ListNode, TreeNode};
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use std::cell::RefCell;
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use std::collections::HashMap;
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use std::rc::Rc;
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/* 函式 */
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fn function() -> i32 {
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    // 執行某些操作
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    return 0;
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}
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/* 常數階 */
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#[allow(unused)]
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fn constant(n: i32) {
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    // 常數、變數、物件佔用 O(1) 空間
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    const A: i32 = 0;
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    let b = 0;
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    let nums = vec![0; 10000];
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    let node = ListNode::new(0);
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    // 迴圈中的變數佔用 O(1) 空間
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    for i in 0..n {
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        let c = 0;
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    }
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    // 迴圈中的函式佔用 O(1) 空間
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    for i in 0..n {
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        function();
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    }
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}
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/* 線性階 */
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#[allow(unused)]
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fn linear(n: i32) {
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    // 長度為 n 的陣列佔用 O(n) 空間
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    let mut nums = vec![0; n as usize];
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    // 長度為 n 的串列佔用 O(n) 空間
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    let mut nodes = Vec::new();
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    for i in 0..n {
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        nodes.push(ListNode::new(i))
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    }
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    // 長度為 n 的雜湊表佔用 O(n) 空間
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    let mut map = HashMap::new();
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    for i in 0..n {
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        map.insert(i, i.to_string());
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    }
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}
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/* 線性階(遞迴實現) */
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fn linear_recur(n: i32) {
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    println!("遞迴 n = {}", n);
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    if n == 1 {
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        return;
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    };
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    linear_recur(n - 1);
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}
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/* 平方階 */
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#[allow(unused)]
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fn quadratic(n: i32) {
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    // 矩陣佔用 O(n^2) 空間
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    let num_matrix = vec![vec![0; n as usize]; n as usize];
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    // 二維串列佔用 O(n^2) 空間
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    let mut num_list = Vec::new();
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    for i in 0..n {
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        let mut tmp = Vec::new();
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        for j in 0..n {
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            tmp.push(0);
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        }
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        num_list.push(tmp);
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    }
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}
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/* 平方階(遞迴實現) */
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fn quadratic_recur(n: i32) -> i32 {
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    if n <= 0 {
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        return 0;
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    };
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    // 陣列 nums 長度為 n, n-1, ..., 2, 1
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    let nums = vec![0; n as usize];
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    println!("遞迴 n = {} 中的 nums 長度 = {}", n, nums.len());
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    return quadratic_recur(n - 1);
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}
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/* 指數階(建立滿二元樹) */
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fn build_tree(n: i32) -> Option<Rc<RefCell<TreeNode>>> {
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    if n == 0 {
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        return None;
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    };
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    let root = TreeNode::new(0);
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    root.borrow_mut().left = build_tree(n - 1);
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    root.borrow_mut().right = build_tree(n - 1);
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    return Some(root);
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}
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/* Driver Code */
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fn main() {
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    let n = 5;
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    // 常數階
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    constant(n);
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    // 線性階
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    linear(n);
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    linear_recur(n);
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    // 平方階
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    quadratic(n);
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    quadratic_recur(n);
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    // 指數階
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    let root = build_tree(n);
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    print_util::print_tree(&root.unwrap());
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}
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