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			37 lines
		
	
	
		
			932 B
		
	
	
	
		
			Ruby
		
	
	
	
	
	
			
		
		
	
	
			37 lines
		
	
	
		
			932 B
		
	
	
	
		
			Ruby
		
	
	
	
	
	
| =begin
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| File: binary_tree_bfs.rb
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| Created Time: 2024-04-18
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| Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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| =end
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| 
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| require_relative '../utils/tree_node'
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| require_relative '../utils/print_util'
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| 
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| ### 层序遍历 ###
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| def level_order(root)
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|   # 初始化队列,加入根节点
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|   queue = [root]
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|   # 初始化一个列表,用于保存遍历序列
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|   res = []
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|   while !queue.empty?
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|     node = queue.shift # 队列出队
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|     res << node.val # 保存节点值
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|     queue << node.left unless node.left.nil? # 左子节点入队
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|     queue << node.right unless node.right.nil? # 右子节点入队
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|   end
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|   res
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| end
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| 
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| ### Driver Code ###
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| if __FILE__ == $0
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|   # 初始化二叉树
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|   # 这里借助了一个从数组直接生成二叉树的函数
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|   root = arr_to_tree([1, 2, 3, 4, 5, 6, 7])
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|   puts "\n初始化二叉树\n\n"
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|   print_tree(root)
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| 
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|   # 层序遍历
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|   res = level_order(root)
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|   puts "\n层序遍历的节点打印序列 = #{res}"
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| end
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