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			55 lines
		
	
	
		
			1.6 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
			
		
		
	
	
			55 lines
		
	
	
		
			1.6 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
| /*
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|  * File: coin_change_greedy.rs
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|  * Created Time: 2023-07-22
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|  * Author: night-cruise (2586447362@qq.com)
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|  */
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| 
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| /* 零钱兑换:贪心 */
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| fn coin_change_greedy(coins: &[i32], mut amt: i32) -> i32 {
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|     // 假设 coins 列表有序
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|     let mut i = coins.len() - 1;
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|     let mut count = 0;
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|     // 循环进行贪心选择,直到无剩余金额
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|     while amt > 0 {
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|         // 找到小于且最接近剩余金额的硬币
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|         while i > 0 && coins[i] > amt {
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|             i -= 1;
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|         }
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|         // 选择 coins[i]
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|         amt -= coins[i];
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|         count += 1;
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|     }
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|     // 若未找到可行方案,则返回 -1
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|     if amt == 0 {
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|         count
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|     } else {
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|         -1
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|     }
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| }
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| 
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| /* Driver Code */
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| fn main() {
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|     // 贪心:能够保证找到全局最优解
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|     let coins = [1, 5, 10, 20, 50, 100];
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|     let amt = 186;
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|     let res = coin_change_greedy(&coins, amt);
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|     println!("\ncoins = {:?}, amt = {}", coins, amt);
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|     println!("凑到 {} 所需的最少硬币数量为 {}", amt, res);
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| 
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|     // 贪心:无法保证找到全局最优解
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|     let coins = [1, 20, 50];
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|     let amt = 60;
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|     let res = coin_change_greedy(&coins, amt);
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|     println!("\ncoins = {:?}, amt = {}", coins, amt);
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|     println!("凑到 {} 所需的最少硬币数量为 {}", amt, res);
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|     println!("实际上需要的最少数量为 3 ,即 20 + 20 + 20");
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| 
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|     // 贪心:无法保证找到全局最优解
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|     let coins = [1, 49, 50];
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|     let amt = 98;
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|     let res = coin_change_greedy(&coins, amt);
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|     println!("\ncoins = {:?}, amt = {}", coins, amt);
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|     println!("凑到 {} 所需的最少硬币数量为 {}", amt, res);
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|     println!("实际上需要的最少数量为 2 ,即 49 + 49");
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| }
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