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			47 lines
		
	
	
		
			1.2 KiB
		
	
	
	
		
			Ruby
		
	
	
	
	
	
			
		
		
	
	
			47 lines
		
	
	
		
			1.2 KiB
		
	
	
	
		
			Ruby
		
	
	
	
	
	
| =begin
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| File: build_tree.rb
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| Created Time: 2024-05-13
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| Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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| =end
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| 
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| require_relative '../utils/tree_node'
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| require_relative '../utils/print_util'
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| 
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| ### 构建二叉树:分治 ###
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| def dfs(preorder, inorder_map, i, l, r)
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|   # 子树区间为空时终止
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|   return if r - l < 0
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| 
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|   # 初始化根节点
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|   root = TreeNode.new(preorder[i])
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|   # 查询 m ,从而划分左右子树
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|   m = inorder_map[preorder[i]]
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|   # 子问题:构建左子树
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|   root.left = dfs(preorder, inorder_map, i + 1, l, m - 1)
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|   # 子问题:构建右子树
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|   root.right = dfs(preorder, inorder_map, i + 1 + m - l, m + 1, r)
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| 
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|   # 返回根节点
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|   root
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| end
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| 
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| ### 构建二叉树 ###
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| def build_tree(preorder, inorder)
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|   # 初始化哈希表,存储 inorder 元素到索引的映射
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|   inorder_map = {}
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|   inorder.each_with_index { |val, i| inorder_map[val] = i }
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|   dfs(preorder, inorder_map, 0, 0, inorder.length - 1)
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| end
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| 
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| ### Driver Code ###
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| if __FILE__ == $0
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|   preorder = [3, 9, 2, 1, 7]
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|   inorder = [9, 3, 1, 2, 7]
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|   puts "前序遍历 = #{preorder}"
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|   puts "中序遍历 = #{inorder}"
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| 
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|   root = build_tree(preorder, inorder)
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|   puts "构建的二叉树为:"
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|   print_tree(root)
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| end
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