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			196 lines
		
	
	
		
			6.5 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
			
		
		
	
	
			196 lines
		
	
	
		
			6.5 KiB
		
	
	
	
		
			Rust
		
	
	
	
	
	
| /*
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|  * File: binary_search_tree.rs
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|  * Created Time: 2023-04-20
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|  * Author: xBLACKICEx (xBLACKICE@outlook.com)、night-cruise (2586447362@qq.com)
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|  */
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| 
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| use hello_algo_rust::include::print_util;
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| 
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| use std::cell::RefCell;
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| use std::cmp::Ordering;
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| use std::rc::Rc;
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| 
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| use hello_algo_rust::include::TreeNode;
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| 
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| type OptionTreeNodeRc = Option<Rc<RefCell<TreeNode>>>;
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| 
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| /* 二叉搜索树 */
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| pub struct BinarySearchTree {
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|     root: OptionTreeNodeRc,
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| }
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| 
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| impl BinarySearchTree {
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|     /* 构造方法 */
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|     pub fn new() -> Self {
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|         // 初始化空树
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|         Self { root: None }
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|     }
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| 
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|     /* 获取二叉树根节点 */
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|     pub fn get_root(&self) -> OptionTreeNodeRc {
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|         self.root.clone()
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|     }
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| 
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|     /* 查找节点 */
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|     pub fn search(&self, num: i32) -> OptionTreeNodeRc {
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|         let mut cur = self.root.clone();
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|         // 循环查找,越过叶节点后跳出
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|         while let Some(node) = cur.clone() {
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|             match num.cmp(&node.borrow().val) {
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|                 // 目标节点在 cur 的右子树中
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|                 Ordering::Greater => cur = node.borrow().right.clone(),
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|                 // 目标节点在 cur 的左子树中
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|                 Ordering::Less => cur = node.borrow().left.clone(),
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|                 // 找到目标节点,跳出循环
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|                 Ordering::Equal => break,
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|             }
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|         }
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| 
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|         // 返回目标节点
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|         cur
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|     }
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| 
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|     /* 插入节点 */
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|     pub fn insert(&mut self, num: i32) {
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|         // 若树为空,则初始化根节点
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|         if self.root.is_none() {
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|             self.root = Some(TreeNode::new(num));
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|             return;
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|         }
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|         let mut cur = self.root.clone();
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|         let mut pre = None;
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|         // 循环查找,越过叶节点后跳出
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|         while let Some(node) = cur.clone() {
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|             match num.cmp(&node.borrow().val) {
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|                 // 找到重复节点,直接返回
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|                 Ordering::Equal => return,
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|                 // 插入位置在 cur 的右子树中
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|                 Ordering::Greater => {
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|                     pre = cur.clone();
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|                     cur = node.borrow().right.clone();
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|                 }
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|                 // 插入位置在 cur 的左子树中
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|                 Ordering::Less => {
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|                     pre = cur.clone();
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|                     cur = node.borrow().left.clone();
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|                 }
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|             }
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|         }
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|         // 插入节点
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|         let pre = pre.unwrap();
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|         let node = Some(TreeNode::new(num));
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|         if num > pre.borrow().val {
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|             pre.borrow_mut().right = node;
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|         } else {
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|             pre.borrow_mut().left = node;
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|         }
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|     }
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| 
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|     /* 删除节点 */
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|     pub fn remove(&mut self, num: i32) {
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|         // 若树为空,直接提前返回
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|         if self.root.is_none() {
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|             return;
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|         }
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|         let mut cur = self.root.clone();
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|         let mut pre = None;
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|         // 循环查找,越过叶节点后跳出
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|         while let Some(node) = cur.clone() {
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|             match num.cmp(&node.borrow().val) {
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|                 // 找到待删除节点,跳出循环
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|                 Ordering::Equal => break,
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|                 // 待删除节点在 cur 的右子树中
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|                 Ordering::Greater => {
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|                     pre = cur.clone();
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|                     cur = node.borrow().right.clone();
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|                 }
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|                 // 待删除节点在 cur 的左子树中
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|                 Ordering::Less => {
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|                     pre = cur.clone();
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|                     cur = node.borrow().left.clone();
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|                 }
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|             }
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|         }
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|         // 若无待删除节点,则直接返回
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|         if cur.is_none() {
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|             return;
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|         }
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|         let cur = cur.unwrap();
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|         let (left_child, right_child) = (cur.borrow().left.clone(), cur.borrow().right.clone());
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|         match (left_child.clone(), right_child.clone()) {
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|             // 子节点数量 = 0 or 1
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|             (None, None) | (Some(_), None) | (None, Some(_)) => {
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|                 // 当子节点数量 = 0 / 1 时, child = nullptr / 该子节点
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|                 let child = left_child.or(right_child);
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|                 let pre = pre.unwrap();
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|                 // 删除节点 cur
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|                 if !Rc::ptr_eq(&cur, self.root.as_ref().unwrap()) {
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|                     let left = pre.borrow().left.clone();
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|                     if left.is_some() && Rc::ptr_eq(left.as_ref().unwrap(), &cur) {
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|                         pre.borrow_mut().left = child;
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|                     } else {
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|                         pre.borrow_mut().right = child;
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|                     }
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|                 } else {
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|                     // 若删除节点为根节点,则重新指定根节点
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|                     self.root = child;
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|                 }
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|             }
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|             // 子节点数量 = 2
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|             (Some(_), Some(_)) => {
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|                 // 获取中序遍历中 cur 的下一个节点
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|                 let mut tmp = cur.borrow().right.clone();
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|                 while let Some(node) = tmp.clone() {
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|                     if node.borrow().left.is_some() {
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|                         tmp = node.borrow().left.clone();
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|                     } else {
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|                         break;
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|                     }
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|                 }
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|                 let tmp_val = tmp.unwrap().borrow().val;
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|                 // 递归删除节点 tmp
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|                 self.remove(tmp_val);
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|                 // 用 tmp 覆盖 cur
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|                 cur.borrow_mut().val = tmp_val;
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|             }
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|         }
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|     }
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| }
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| 
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| /* Driver Code */
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| fn main() {
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|     /* 初始化二叉搜索树 */
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|     let mut bst = BinarySearchTree::new();
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|     // 请注意,不同的插入顺序会生成不同的二叉树,该序列可以生成一个完美二叉树
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|     let nums = [8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15];
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|     for &num in &nums {
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|         bst.insert(num);
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|     }
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|     println!("\n初始化的二叉树为\n");
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|     print_util::print_tree(bst.get_root().as_ref().unwrap());
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| 
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|     /* 查找结点 */
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|     let node = bst.search(7);
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|     println!(
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|         "\n查找到的节点对象为 {:?},节点值 = {}",
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|         node.clone().unwrap(),
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|         node.clone().unwrap().borrow().val
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|     );
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| 
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|     /* 插入节点 */
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|     bst.insert(16);
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|     println!("\n插入节点 16 后,二叉树为\n");
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|     print_util::print_tree(bst.get_root().as_ref().unwrap());
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| 
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|     /* 删除节点 */
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|     bst.remove(1);
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|     println!("\n删除节点 1 后,二叉树为\n");
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|     print_util::print_tree(bst.get_root().as_ref().unwrap());
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|     bst.remove(2);
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|     println!("\n删除节点 2 后,二叉树为\n");
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|     print_util::print_tree(bst.get_root().as_ref().unwrap());
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|     bst.remove(4);
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|     println!("\n删除节点 4 后,二叉树为\n");
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|     print_util::print_tree(bst.get_root().as_ref().unwrap());
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| }
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