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	e720aa2d24
	
	
	
		
			
			* Sync recent changes to the revised Word. * Revised the preface chapter * Revised the introduction chapter * Revised the computation complexity chapter * Revised the chapter data structure * Revised the chapter array and linked list * Revised the chapter stack and queue * Revised the chapter hashing * Revised the chapter tree * Revised the chapter heap * Revised the chapter graph * Revised the chapter searching * Reivised the sorting chapter * Revised the divide and conquer chapter * Revised the chapter backtacking * Revised the DP chapter * Revised the greedy chapter * Revised the appendix chapter * Revised the preface chapter doubly * Revised the figures
		
			
				
	
	
		
			61 lines
		
	
	
		
			2.0 KiB
		
	
	
	
		
			JavaScript
		
	
	
	
	
	
			
		
		
	
	
			61 lines
		
	
	
		
			2.0 KiB
		
	
	
	
		
			JavaScript
		
	
	
	
	
	
| /**
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|  * File: binary_search.js
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|  * Created Time: 2022-12-22
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|  * Author: JoseHung (szhong@link.cuhk.edu.hk)
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|  */
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| 
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| /* 二分查找(双闭区间) */
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| function binarySearch(nums, target) {
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|     // 初始化双闭区间 [0, n-1] ,即 i, j 分别指向数组首元素、尾元素
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|     let i = 0,
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|         j = nums.length - 1;
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|     // 循环,当搜索区间为空时跳出(当 i > j 时为空)
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|     while (i <= j) {
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|         // 计算中点索引 m ,使用 parseInt() 向下取整
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|         const m = parseInt(i + (j - i) / 2);
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|         if (nums[m] < target)
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|             // 此情况说明 target 在区间 [m+1, j] 中
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|             i = m + 1;
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|         else if (nums[m] > target)
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|             // 此情况说明 target 在区间 [i, m-1] 中
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|             j = m - 1;
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|         else return m; // 找到目标元素,返回其索引
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|     }
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|     // 未找到目标元素,返回 -1
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|     return -1;
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| }
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| 
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| /* 二分查找(左闭右开区间) */
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| function binarySearchLCRO(nums, target) {
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|     // 初始化左闭右开区间 [0, n) ,即 i, j 分别指向数组首元素、尾元素+1
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|     let i = 0,
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|         j = nums.length;
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|     // 循环,当搜索区间为空时跳出(当 i = j 时为空)
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|     while (i < j) {
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|         // 计算中点索引 m ,使用 parseInt() 向下取整
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|         const m = parseInt(i + (j - i) / 2);
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|         if (nums[m] < target)
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|             // 此情况说明 target 在区间 [m+1, j) 中
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|             i = m + 1;
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|         else if (nums[m] > target)
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|             // 此情况说明 target 在区间 [i, m) 中
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|             j = m;
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|         // 找到目标元素,返回其索引
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|         else return m;
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|     }
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|     // 未找到目标元素,返回 -1
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|     return -1;
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| }
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| 
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| /* Driver Code */
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| const target = 6;
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| const nums = [1, 3, 6, 8, 12, 15, 23, 26, 31, 35];
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| 
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| /* 二分查找(双闭区间) */
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| let index = binarySearch(nums, target);
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| console.log('目标元素 6 的索引 = ' + index);
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| 
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| /* 二分查找(左闭右开区间) */
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| index = binarySearchLCRO(nums, target);
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| console.log('目标元素 6 的索引 = ' + index);
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