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			68 lines
		
	
	
		
			2.1 KiB
		
	
	
	
		
			Java
		
	
	
	
	
	
			
		
		
	
	
			68 lines
		
	
	
		
			2.1 KiB
		
	
	
	
		
			Java
		
	
	
	
	
	
| /**
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|  * File: coin_change_ii.java
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|  * Created Time: 2023-07-11
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|  * Author: krahets (krahets@163.com)
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|  */
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| 
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| package chapter_dynamic_programming;
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| 
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| public class coin_change_ii {
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|     /* 零钱兑换 II:动态规划 */
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|     static int coinChangeIIDP(int[] coins, int amt) {
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|         int n = coins.length;
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|         // 初始化 dp 表
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|         int[][] dp = new int[n + 1][amt + 1];
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|         // 初始化首列
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|         for (int i = 0; i <= n; i++) {
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|             dp[i][0] = 1;
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|         }
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|         // 状态转移
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|         for (int i = 1; i <= n; i++) {
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|             for (int a = 1; a <= amt; a++) {
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|                 if (coins[i - 1] > a) {
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|                     // 若超过目标金额,则不选硬币 i
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|                     dp[i][a] = dp[i - 1][a];
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|                 } else {
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|                     // 不选和选硬币 i 这两种方案之和
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|                     dp[i][a] = dp[i - 1][a] + dp[i][a - coins[i - 1]];
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|                 }
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|             }
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|         }
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|         return dp[n][amt];
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|     }
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| 
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|     /* 零钱兑换 II:空间优化后的动态规划 */
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|     static int coinChangeIIDPComp(int[] coins, int amt) {
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|         int n = coins.length;
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|         // 初始化 dp 表
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|         int[] dp = new int[amt + 1];
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|         dp[0] = 1;
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|         // 状态转移
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|         for (int i = 1; i <= n; i++) {
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|             for (int a = 1; a <= amt; a++) {
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|                 if (coins[i - 1] > a) {
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|                     // 若超过目标金额,则不选硬币 i
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|                     dp[a] = dp[a];
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|                 } else {
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|                     // 不选和选硬币 i 这两种方案之和
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|                     dp[a] = dp[a] + dp[a - coins[i - 1]];
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|                 }
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|             }
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|         }
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|         return dp[amt];
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|     }
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| 
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|     public static void main(String[] args) {
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|         int[] coins = { 1, 2, 5 };
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|         int amt = 5;
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| 
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|         // 动态规划
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|         int res = coinChangeIIDP(coins, amt);
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|         System.out.println("凑出目标金额的硬币组合数量为 " + res);
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| 
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|         // 空间优化后的动态规划
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|         res = coinChangeIIDPComp(coins, amt);
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|         System.out.println("凑出目标金额的硬币组合数量为 " + res);
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|     }
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| }
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