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			62 lines
		
	
	
		
			1.8 KiB
		
	
	
	
		
			Dart
		
	
	
	
	
	
			
		
		
	
	
			62 lines
		
	
	
		
			1.8 KiB
		
	
	
	
		
			Dart
		
	
	
	
	
	
| /**
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|  * File: subset_sum_ii.dart
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|  * Created Time: 2023-08-10
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|  * Author: liuyuxin (gvenusleo@gmail.com)
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|  */
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| 
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| /* 回溯算法:子集和 II */
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| void backtrack(
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|   List<int> state,
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|   int target,
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|   List<int> choices,
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|   int start,
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|   List<List<int>> res,
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| ) {
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|   // 子集和等于 target 时,记录解
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|   if (target == 0) {
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|     res.add(List.from(state));
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|     return;
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|   }
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|   // 遍历所有选择
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|   // 剪枝二:从 start 开始遍历,避免生成重复子集
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|   // 剪枝三:从 start 开始遍历,避免重复选择同一元素
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|   for (int i = start; i < choices.length; i++) {
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|     // 剪枝一:若子集和超过 target ,则直接结束循环
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|     // 这是因为数组已排序,后边元素更大,子集和一定超过 target
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|     if (target - choices[i] < 0) {
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|       break;
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|     }
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|     // 剪枝四:如果该元素与左边元素相等,说明该搜索分支重复,直接跳过
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|     if (i > start && choices[i] == choices[i - 1]) {
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|       continue;
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|     }
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|     // 尝试:做出选择,更新 target, start
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|     state.add(choices[i]);
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|     // 进行下一轮选择
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|     backtrack(state, target - choices[i], choices, i + 1, res);
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|     // 回退:撤销选择,恢复到之前的状态
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|     state.removeLast();
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|   }
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| }
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| 
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| /* 求解子集和 II */
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| List<List<int>> subsetSumII(List<int> nums, int target) {
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|   List<int> state = []; // 状态(子集)
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|   nums.sort(); // 对 nums 进行排序
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|   int start = 0; // 遍历起始点
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|   List<List<int>> res = []; // 结果列表(子集列表)
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|   backtrack(state, target, nums, start, res);
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|   return res;
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| }
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| 
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| /* Driver Code */
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| void main() {
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|   List<int> nums = [4, 4, 5];
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|   int target = 9;
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| 
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|   List<List<int>> res = subsetSumII(nums, target);
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| 
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|   print("输入数组 nums = $nums, target = $target");
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|   print("所有和等于 $target 的子集 res = $res");
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| }
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