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			* Update the book with the thrid revised edition * Fix a typo * Update the contributors' information * Update the mindmap * Update the version number
		
			
				
	
	
		
			77 lines
		
	
	
		
			2.7 KiB
		
	
	
	
		
			C#
		
	
	
	
	
	
			
		
		
	
	
			77 lines
		
	
	
		
			2.7 KiB
		
	
	
	
		
			C#
		
	
	
	
	
	
| /**
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|  * File: n_queens.cs
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|  * Created Time: 2023-05-04
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|  * Author: hpstory (hpstory1024@163.com)
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|  */
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| 
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| namespace hello_algo.chapter_backtracking;
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| 
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| public class n_queens {
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|     /* 回溯算法:n 皇后 */
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|     void Backtrack(int row, int n, List<List<string>> state, List<List<List<string>>> res,
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|             bool[] cols, bool[] diags1, bool[] diags2) {
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|         // 当放置完所有行时,记录解
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|         if (row == n) {
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|             List<List<string>> copyState = [];
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|             foreach (List<string> sRow in state) {
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|                 copyState.Add(new List<string>(sRow));
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|             }
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|             res.Add(copyState);
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|             return;
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|         }
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|         // 遍历所有列
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|         for (int col = 0; col < n; col++) {
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|             // 计算该格子对应的主对角线和次对角线
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|             int diag1 = row - col + n - 1;
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|             int diag2 = row + col;
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|             // 剪枝:不允许该格子所在列、主对角线、次对角线上存在皇后
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|             if (!cols[col] && !diags1[diag1] && !diags2[diag2]) {
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|                 // 尝试:将皇后放置在该格子
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|                 state[row][col] = "Q";
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|                 cols[col] = diags1[diag1] = diags2[diag2] = true;
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|                 // 放置下一行
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|                 Backtrack(row + 1, n, state, res, cols, diags1, diags2);
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|                 // 回退:将该格子恢复为空位
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|                 state[row][col] = "#";
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|                 cols[col] = diags1[diag1] = diags2[diag2] = false;
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|             }
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|         }
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|     }
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| 
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|     /* 求解 n 皇后 */
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|     List<List<List<string>>> NQueens(int n) {
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|         // 初始化 n*n 大小的棋盘,其中 'Q' 代表皇后,'#' 代表空位
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|         List<List<string>> state = [];
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|         for (int i = 0; i < n; i++) {
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|             List<string> row = [];
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|             for (int j = 0; j < n; j++) {
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|                 row.Add("#");
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|             }
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|             state.Add(row);
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|         }
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|         bool[] cols = new bool[n]; // 记录列是否有皇后
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|         bool[] diags1 = new bool[2 * n - 1]; // 记录主对角线上是否有皇后
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|         bool[] diags2 = new bool[2 * n - 1]; // 记录次对角线上是否有皇后
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|         List<List<List<string>>> res = [];
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| 
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|         Backtrack(0, n, state, res, cols, diags1, diags2);
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| 
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|         return res;
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|     }
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| 
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|     [Test]
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|     public void Test() {
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|         int n = 4;
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|         List<List<List<string>>> res = NQueens(n);
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| 
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|         Console.WriteLine("输入棋盘长宽为 " + n);
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|         Console.WriteLine("皇后放置方案共有 " + res.Count + " 种");
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|         foreach (List<List<string>> state in res) {
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|             Console.WriteLine("--------------------");
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|             foreach (List<string> row in state) {
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|                 PrintUtil.PrintList(row);
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|             }
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|         }
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|     }
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| }
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