Format the Java codes with the Reat Hat extension.

This commit is contained in:
krahets
2023-04-14 00:12:10 +08:00
parent 7273ee24e8
commit f8513455b5
39 changed files with 195 additions and 205 deletions

View File

@ -15,7 +15,7 @@ class BinarySearchTree {
public BinarySearchTree(int[] nums) {
Arrays.sort(nums); // 排序数组
root = buildTree(nums, 0, nums.length - 1); // 构建二叉搜索树
root = buildTree(nums, 0, nums.length - 1); // 构建二叉搜索树
}
/* 获取二叉树根节点 */
@ -25,7 +25,8 @@ class BinarySearchTree {
/* 构建二叉搜索树 */
public TreeNode buildTree(int[] nums, int i, int j) {
if (i > j) return null;
if (i > j)
return null;
// 将数组中间节点作为根节点
int mid = (i + j) / 2;
TreeNode root = new TreeNode(nums[mid]);
@ -41,11 +42,14 @@ class BinarySearchTree {
// 循环查找,越过叶节点后跳出
while (cur != null) {
// 目标节点在 cur 的右子树中
if (cur.val < num) cur = cur.right;
if (cur.val < num)
cur = cur.right;
// 目标节点在 cur 的左子树中
else if (cur.val > num) cur = cur.left;
else if (cur.val > num)
cur = cur.left;
// 找到目标节点,跳出循环
else break;
else
break;
}
// 返回目标节点
return cur;
@ -54,49 +58,62 @@ class BinarySearchTree {
/* 插入节点 */
public TreeNode insert(int num) {
// 若树为空,直接提前返回
if (root == null) return null;
if (root == null)
return null;
TreeNode cur = root, pre = null;
// 循环查找,越过叶节点后跳出
while (cur != null) {
// 找到重复节点,直接返回
if (cur.val == num) return null;
if (cur.val == num)
return null;
pre = cur;
// 插入位置在 cur 的右子树中
if (cur.val < num) cur = cur.right;
if (cur.val < num)
cur = cur.right;
// 插入位置在 cur 的左子树中
else cur = cur.left;
else
cur = cur.left;
}
// 插入节点 val
TreeNode node = new TreeNode(num);
if (pre.val < num) pre.right = node;
else pre.left = node;
if (pre.val < num)
pre.right = node;
else
pre.left = node;
return node;
}
/* 删除节点 */
public TreeNode remove(int num) {
// 若树为空,直接提前返回
if (root == null) return null;
if (root == null)
return null;
TreeNode cur = root, pre = null;
// 循环查找,越过叶节点后跳出
while (cur != null) {
// 找到待删除节点,跳出循环
if (cur.val == num) break;
if (cur.val == num)
break;
pre = cur;
// 待删除节点在 cur 的右子树中
if (cur.val < num) cur = cur.right;
if (cur.val < num)
cur = cur.right;
// 待删除节点在 cur 的左子树中
else cur = cur.left;
else
cur = cur.left;
}
// 若无待删除节点,则直接返回
if (cur == null) return null;
if (cur == null)
return null;
// 子节点数量 = 0 or 1
if (cur.left == null || cur.right == null) {
// 当子节点数量 = 0 / 1 时, child = null / 该子节点
TreeNode child = cur.left != null ? cur.left : cur.right;
// 删除节点 cur
if (pre.left == cur) pre.left = child;
else pre.right = child;
if (pre.left == cur)
pre.left = child;
else
pre.right = child;
}
// 子节点数量 = 2
else {
@ -113,7 +130,8 @@ class BinarySearchTree {
/* 获取中序遍历中的下一个节点(仅适用于 root 有左子节点的情况) */
public TreeNode getInOrderNext(TreeNode root) {
if (root == null) return root;
if (root == null)
return root;
// 循环访问左子节点,直到叶节点时为最小节点,跳出
while (root.left != null) {
root = root.left;