Fix the return type of binary search tree and avl tree

This commit is contained in:
krahets
2023-04-14 05:47:20 +08:00
parent 9c9c8b7574
commit f7ae9c8a02
24 changed files with 247 additions and 451 deletions

View File

@ -92,10 +92,9 @@ class AVLTree:
# 平衡树,无需旋转,直接返回
return node
def insert(self, val) -> TreeNode:
def insert(self, val) -> None:
"""插入节点"""
self.__root = self.__insert_helper(self.__root, val)
return self.__root
def __insert_helper(self, node: TreeNode | None, val: int) -> TreeNode:
"""递归插入节点(辅助方法)"""
@ -114,10 +113,9 @@ class AVLTree:
# 2. 执行旋转操作,使该子树重新恢复平衡
return self.__rotate(node)
def remove(self, val: int) -> TreeNode | None:
def remove(self, val: int) -> None:
"""删除节点"""
self.__root = self.__remove_helper(self.__root, val)
return self.__root
def __remove_helper(self, node: TreeNode | None, val: int) -> TreeNode | None:
"""递归删除节点(辅助方法)"""
@ -137,8 +135,11 @@ class AVLTree:
# 子节点数量 = 1 ,直接删除 node
else:
node = child
else: # 子节点数量 = 2 ,则将中序遍历的下个节点删除,并用该节点替换当前节点
temp = self.__get_inorder_next(node.right)
else:
# 子节点数量 = 2 ,则将中序遍历的下个节点删除,并用该节点替换当前节点
temp = node.right
while temp.left is not None:
temp = temp.left
node.right = self.__remove_helper(node.right, temp.val)
node.val = temp.val
# 更新节点高度
@ -146,15 +147,6 @@ class AVLTree:
# 2. 执行旋转操作,使该子树重新恢复平衡
return self.__rotate(node)
def __get_inorder_next(self, node: TreeNode | None) -> TreeNode | None:
"""获取中序遍历中的下一个节点(仅适用于 root 有左子节点的情况)"""
if node is None:
return None
# 循环访问左子节点,直到叶节点时为最小节点,跳出
while node.left is not None:
node = node.left
return node
def search(self, val: int) -> TreeNode | None:
"""查找节点"""
cur = self.__root