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Update the book based on the revised second edition (#1014)
* Revised the book * Update the book with the second revised edition * Revise base on the manuscript of the first edition
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@ -21,10 +21,10 @@ public class n_queens {
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}
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// 遍历所有列
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for (int col = 0; col < n; col++) {
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// 计算该格子对应的主对角线和副对角线
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// 计算该格子对应的主对角线和次对角线
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int diag1 = row - col + n - 1;
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int diag2 = row + col;
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// 剪枝:不允许该格子所在列、主对角线、副对角线上存在皇后
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// 剪枝:不允许该格子所在列、主对角线、次对角线上存在皇后
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if (!cols[col] && !diags1[diag1] && !diags2[diag2]) {
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// 尝试:将皇后放置在该格子
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state[row][col] = "Q";
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@ -51,7 +51,7 @@ public class n_queens {
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}
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bool[] cols = new bool[n]; // 记录列是否有皇后
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bool[] diags1 = new bool[2 * n - 1]; // 记录主对角线上是否有皇后
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bool[] diags2 = new bool[2 * n - 1]; // 记录副对角线上是否有皇后
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bool[] diags2 = new bool[2 * n - 1]; // 记录次对角线上是否有皇后
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List<List<List<string>>> res = [];
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Backtrack(0, n, state, res, cols, diags1, diags2);
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