algorithm/hello-algo
1
0
Fork 0
mirror of https://github.com/krahets/hello-algo.git synced 2025-11-02 21:24:53 +08:00
Code Issues Packages Projects Releases Wiki Activity

style: use string interpolation in print

Browse Source
This commit is contained in:
nuomi1
2023-01-08 20:54:40 +08:00
parent 3b52df2a8f
commit f3e9c2cf89
3 changed files with 16 additions and 16 deletions
Download Patch File Download Diff File Expand all files Collapse all files

24
codes/swift/chapter_computational_complexity/time_complexity.swift
View File

@ -137,36 +137,36 @@ enum TimeComplexity {
static func main() {
// 可以修改 n 运行，体会一下各种复杂度的操作数量变化趋势
let n = 8
print("输入数据大小 n =", n)
print("输入数据大小 n = \(n)")
var count = constant(n: n)
print("常数阶的计算操作数量 =", count)
print("常数阶的计算操作数量 = \(count)")
count = linear(n: n)
print("线性阶的计算操作数量 =", count)
print("线性阶的计算操作数量 = \(count)")
count = arrayTraversal(nums: Array(repeating: 0, count: n))
print("线性阶（遍历数组）的计算操作数量 =", count)
print("线性阶（遍历数组）的计算操作数量 = \(count)")
count = quadratic(n: n)
print("平方阶的计算操作数量 =", count)
print("平方阶的计算操作数量 = \(count)")
var nums = Array(sequence(first: n, next: { $0 > 0 ? $0 - 1 : nil })) // [n,n-1,...,2,1]
count = bubbleSort(nums: &nums)
print("平方阶（冒泡排序）的计算操作数量 =", count)
print("平方阶（冒泡排序）的计算操作数量 = \(count)")
count = exponential(n: n)
print("指数阶（循环实现）的计算操作数量 =", count)
print("指数阶（循环实现）的计算操作数量 = \(count)")
count = expRecur(n: n)
print("指数阶（递归实现）的计算操作数量 =", count)
print("指数阶（递归实现）的计算操作数量 = \(count)")
count = logarithmic(n: n)
print("对数阶（循环实现）的计算操作数量 =", count)
print("对数阶（循环实现）的计算操作数量 = \(count)")
count = logRecur(n: n)
print("对数阶（递归实现）的计算操作数量 =", count)
print("对数阶（递归实现）的计算操作数量 = \(count)")
count = linearLogRecur(n: Double(n))
print("线性对数阶（递归实现）的计算操作数量 =", count)
print("线性对数阶（递归实现）的计算操作数量 = \(count)")
count = factorialRecur(n: n)
print("阶乘阶（递归实现）的计算操作数量 =", count)
print("阶乘阶（递归实现）的计算操作数量 = \(count)")
}
}