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<li>同理，对剩余 <span class="arithmatex">\(n - 1\)</span> 个元素执行「冒泡」，可将第二大元素交换至正确位置，因而待排序元素只剩 <span class="arithmatex">\(n - 2\)</span> 个。</li>
<li>以此类推…… <strong>循环 <span class="arithmatex">\(n - 1\)</span> 轮「冒泡」，即可完成整个数组的排序</strong>。</li>
</ol>
<p><img alt="bubble_sort_overview" src="../bubble_sort.assets/bubble_sort_overview.png" /></p>
<p align="center"> Fig. 冒泡排序流程 </p>
<p><img alt="冒泡排序流程" src="../bubble_sort.assets/bubble_sort_overview.png" /></p>
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