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feat: Revised the book (#978)
* Sync recent changes to the revised Word. * Revised the preface chapter * Revised the introduction chapter * Revised the computation complexity chapter * Revised the chapter data structure * Revised the chapter array and linked list * Revised the chapter stack and queue * Revised the chapter hashing * Revised the chapter tree * Revised the chapter heap * Revised the chapter graph * Revised the chapter searching * Reivised the sorting chapter * Revised the divide and conquer chapter * Revised the chapter backtacking * Revised the DP chapter * Revised the greedy chapter * Revised the appendix chapter * Revised the preface chapter doubly * Revised the figures
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@ -12,7 +12,7 @@ def bucket_sort(nums: list[float]):
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buckets = [[] for _ in range(k)]
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# 1. 将数组元素分配到各个桶中
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for num in nums:
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# 输入数据范围 [0, 1),使用 num * k 映射到索引范围 [0, k-1]
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# 输入数据范围为 [0, 1),使用 num * k 映射到索引范围 [0, k-1]
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i = int(num * k)
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# 将 num 添加进桶 i
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buckets[i].append(num)
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@ -32,7 +32,7 @@ def heap_sort(nums: list[int]):
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sift_down(nums, len(nums), i)
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# 从堆中提取最大元素,循环 n-1 轮
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for i in range(len(nums) - 1, 0, -1):
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# 交换根节点与最右叶节点(即交换首元素与尾元素)
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# 交换根节点与最右叶节点(交换首元素与尾元素)
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nums[0], nums[i] = nums[i], nums[0]
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# 以根节点为起点,从顶至底进行堆化
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sift_down(nums, i, 0)
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@ -10,7 +10,7 @@ class QuickSort:
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def partition(self, nums: list[int], left: int, right: int) -> int:
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"""哨兵划分"""
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# 以 nums[left] 作为基准数
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# 以 nums[left] 为基准数
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i, j = left, right
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while i < j:
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while i < j and nums[j] >= nums[left]:
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@ -50,11 +50,11 @@ class QuickSortMedian:
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def partition(self, nums: list[int], left: int, right: int) -> int:
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"""哨兵划分(三数取中值)"""
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# 以 nums[left] 作为基准数
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# 以 nums[left] 为基准数
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med = self.median_three(nums, left, (left + right) // 2, right)
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# 将中位数交换至数组最左端
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nums[left], nums[med] = nums[med], nums[left]
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# 以 nums[left] 作为基准数
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# 以 nums[left] 为基准数
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i, j = left, right
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while i < j:
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while i < j and nums[j] >= nums[left]:
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@ -84,7 +84,7 @@ class QuickSortTailCall:
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def partition(self, nums: list[int], left: int, right: int) -> int:
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"""哨兵划分"""
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# 以 nums[left] 作为基准数
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# 以 nums[left] 为基准数
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i, j = left, right
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while i < j:
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while i < j and nums[j] >= nums[left]:
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@ -103,7 +103,7 @@ class QuickSortTailCall:
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while left < right:
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# 哨兵划分操作
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pivot = self.partition(nums, left, right)
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# 对两个子数组中较短的那个执行快排
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# 对两个子数组中较短的那个执行快速排序
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if pivot - left < right - pivot:
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self.quick_sort(nums, left, pivot - 1) # 递归排序左子数组
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left = pivot + 1 # 剩余未排序区间为 [pivot + 1, right]
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@ -13,7 +13,7 @@ def digit(num: int, exp: int) -> int:
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def counting_sort_digit(nums: list[int], exp: int):
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"""计数排序(根据 nums 第 k 位排序)"""
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# 十进制的位范围为 0~9 ,因此需要长度为 10 的桶
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# 十进制的位范围为 0~9 ,因此需要长度为 10 的桶数组
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counter = [0] * 10
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n = len(nums)
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# 统计 0~9 各数字的出现次数
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