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feat: Revised the book (#978)
* Sync recent changes to the revised Word. * Revised the preface chapter * Revised the introduction chapter * Revised the computation complexity chapter * Revised the chapter data structure * Revised the chapter array and linked list * Revised the chapter stack and queue * Revised the chapter hashing * Revised the chapter tree * Revised the chapter heap * Revised the chapter graph * Revised the chapter searching * Reivised the sorting chapter * Revised the divide and conquer chapter * Revised the chapter backtacking * Revised the DP chapter * Revised the greedy chapter * Revised the appendix chapter * Revised the preface chapter doubly * Revised the figures
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@ -25,7 +25,7 @@ void backtrack(vector<int> &choices, int state, int n, vector<int> &res) {
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/* 爬楼梯:回溯 */
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int climbingStairsBacktrack(int n) {
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vector<int> choices = {1, 2}; // 可选择向上爬 1 或 2 阶
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vector<int> choices = {1, 2}; // 可选择向上爬 1 阶或 2 阶
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int state = 0; // 从第 0 阶开始爬
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vector<int> res = {0}; // 使用 res[0] 记录方案数量
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backtrack(choices, state, n, res);
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@ -16,7 +16,7 @@ int coinChangeDP(vector<int> &coins, int amt) {
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for (int a = 1; a <= amt; a++) {
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dp[0][a] = MAX;
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}
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// 状态转移:其余行列
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// 状态转移:其余行和列
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for (int i = 1; i <= n; i++) {
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for (int a = 1; a <= amt; a++) {
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if (coins[i - 1] > a) {
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@ -65,7 +65,7 @@ int editDistanceDP(string s, string t) {
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for (int j = 1; j <= m; j++) {
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dp[0][j] = j;
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}
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// 状态转移:其余行列
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// 状态转移:其余行和列
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for (int i = 1; i <= n; i++) {
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for (int j = 1; j <= m; j++) {
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if (s[i - 1] == t[j - 1]) {
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@ -6,11 +6,11 @@ using namespace std;
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/* 0-1 背包:暴力搜索 */
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int knapsackDFS(vector<int> &wgt, vector<int> &val, int i, int c) {
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// 若已选完所有物品或背包无容量,则返回价值 0
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// 若已选完所有物品或背包无剩余容量,则返回价值 0
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if (i == 0 || c == 0) {
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return 0;
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}
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// 若超过背包容量,则只能不放入背包
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// 若超过背包容量,则只能选择不放入背包
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if (wgt[i - 1] > c) {
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return knapsackDFS(wgt, val, i - 1, c);
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}
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@ -23,7 +23,7 @@ int knapsackDFS(vector<int> &wgt, vector<int> &val, int i, int c) {
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/* 0-1 背包:记忆化搜索 */
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int knapsackDFSMem(vector<int> &wgt, vector<int> &val, vector<vector<int>> &mem, int i, int c) {
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// 若已选完所有物品或背包无容量,则返回价值 0
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// 若已选完所有物品或背包无剩余容量,则返回价值 0
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if (i == 0 || c == 0) {
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return 0;
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}
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@ -31,7 +31,7 @@ int knapsackDFSMem(vector<int> &wgt, vector<int> &val, vector<vector<int>> &mem,
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if (mem[i][c] != -1) {
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return mem[i][c];
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}
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// 若超过背包容量,则只能不放入背包
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// 若超过背包容量,则只能选择不放入背包
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if (wgt[i - 1] > c) {
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return knapsackDFSMem(wgt, val, mem, i - 1, c);
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}
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@ -59,7 +59,7 @@ int minPathSumDP(vector<vector<int>> &grid) {
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for (int i = 1; i < n; i++) {
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dp[i][0] = dp[i - 1][0] + grid[i][0];
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}
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// 状态转移:其余行列
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// 状态转移:其余行和列
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for (int i = 1; i < n; i++) {
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for (int j = 1; j < m; j++) {
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dp[i][j] = min(dp[i][j - 1], dp[i - 1][j]) + grid[i][j];
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