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Re-implement merge sort function. (#888)
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@ -1,39 +1,38 @@
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"""
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File: merge_sort.py
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Created Time: 2022-11-25
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Author: timi (xisunyy@163.com)
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Author: timi (xisunyy@163.com), Krahets (krahets@163.com)
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"""
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def merge(nums: list[int], left: int, mid: int, right: int):
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"""合并左子数组和右子数组"""
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# 左子数组区间 [left, mid]
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# 右子数组区间 [mid + 1, right]
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# 初始化辅助数组
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tmp = list(nums[left : right + 1])
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# 左子数组的起始索引和结束索引
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left_start = 0
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left_end = mid - left
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# 右子数组的起始索引和结束索引
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right_start = mid + 1 - left
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right_end = right - left
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# i, j 分别指向左子数组、右子数组的首元素
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i = left_start
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j = right_start
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# 通过覆盖原数组 nums 来合并左子数组和右子数组
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for k in range(left, right + 1):
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# 若“左子数组已全部合并完”,则选取右子数组元素,并且 j++
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if i > left_end:
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nums[k] = tmp[j]
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j += 1
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# 否则,若“右子数组已全部合并完”或“左子数组元素 <= 右子数组元素”,则选取左子数组元素,并且 i++
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elif j > right_end or tmp[i] <= tmp[j]:
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nums[k] = tmp[i]
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# 左子数组区间 [left, mid], 右子数组区间 [mid+1, right]
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# 创建一个临时数组 tmp ,用于存放合并后的结果
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tmp = [0] * (right - left + 1)
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# 初始化左子数组和右子数组的起始索引
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i, j, k = left, mid + 1, 0
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# 当左右子数组都还有元素时,比较并将较小的元素复制到临时数组中
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while i <= mid and j <= right:
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if nums[i] <= nums[j]:
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tmp[k] = nums[i]
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i += 1
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# 否则,若“左右子数组都未全部合并完”且“左子数组元素 > 右子数组元素”,则选取右子数组元素,并且 j++
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else:
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nums[k] = tmp[j]
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tmp[k] = nums[j]
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j += 1
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k += 1
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# 将左子数组和右子数组的剩余元素复制到临时数组中
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while i <= mid:
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tmp[k] = nums[i]
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i += 1
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k += 1
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while j <= right:
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tmp[k] = nums[j]
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j += 1
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k += 1
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# 将临时数组 tmp 中的元素复制回原数组 nums 的对应区间
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for k in range(0, len(tmp)):
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nums[left + k] = tmp[k]
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def merge_sort(nums: list[int], left: int, right: int):
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