Merge branch 'master' into binary_search_tree

This commit is contained in:
Yudong Jin
2023-01-10 13:30:38 +08:00
committed by GitHub
215 changed files with 5618 additions and 1642 deletions

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/*
/**
* File: array.ts
* Created Time: 2022-12-04
* Author: Justin (xiefahit@gmail.com)

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/*
/**
* File: linked_list.ts
* Created Time: 2022-12-10
* Author: Justin (xiefahit@gmail.com)

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/*
/**
* File: list.ts
* Created Time: 2022-12-10
* Author: Justin (xiefahit@gmail.com)

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/*
/**
* File: my_list.ts
* Created Time: 2022-12-11
* Author: Justin (xiefahit@gmail.com)

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/*
/**
* File: leetcode_two_sum.ts
* Created Time: 2022-12-15
* Author: gyt95 (gytkwan@gmail.com)

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/**
* File: time_complexity.ts
* Created Time: 2023-01-02
* Author: RiverTwilight (contact@rene.wang)
*/
/* 常数阶 */
function constant(n: number): number {
let count = 0;
const size = 100000;
for (let i = 0; i < size; i++) count++;
return count;
}
/* 线性阶 */
function linear(n: number): number {
let count = 0;
for (let i = 0; i < n; i++) count++;
return count;
}
/* 线性阶(遍历数组) */
function arrayTraversal(nums: number[]): number {
let count = 0;
// 循环次数与数组长度成正比
for (let i = 0; i < nums.length; i++) {
count++;
}
return count;
}
/* 平方阶 */
function quadratic(n: number): number {
let count = 0;
// 循环次数与数组长度成平方关系
for (let i = 0; i < n; i++) {
for (let j = 0; j < n; j++) {
count++;
}
}
return count;
}
/* 平方阶(冒泡排序) */
function bubbleSort(nums: number[]): number {
let count = 0; // 计数器
// 外循环:待排序元素数量为 n-1, n-2, ..., 1
for (let i = nums.length - 1; i > 0; i--) {
// 内循环:冒泡操作
for (let j = 0; j < i; j++) {
if (nums[j] > nums[j + 1]) {
// 交换 nums[j] 与 nums[j + 1]
let tmp = nums[j];
nums[j] = nums[j + 1];
nums[j + 1] = tmp;
count += 3; // 元素交换包含 3 个单元操作
}
}
}
return count;
}
/* 指数阶(循环实现) */
function exponential(n: number): number {
let count = 0,
base = 1;
// cell 每轮一分为二,形成数列 1, 2, 4, 8, ..., 2^(n-1)
for (let i = 0; i < n; i++) {
for (let j = 0; j < base; j++) {
count++;
}
base *= 2;
}
// count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1
return count;
}
/* 指数阶(递归实现) */
function expRecur(n: number): number {
if (n == 1) return 1;
return expRecur(n - 1) + expRecur(n - 1) + 1;
}
/* 对数阶(循环实现) */
function logarithmic(n: number): number {
let count = 0;
while (n > 1) {
n = n / 2;
count++;
}
return count;
}
/* 对数阶(递归实现) */
function logRecur(n: number): number {
if (n <= 1) return 0;
return logRecur(n / 2) + 1;
}
/* 线性对数阶 */
function linearLogRecur(n: number): number {
if (n <= 1) return 1;
let count = linearLogRecur(n / 2) + linearLogRecur(n / 2);
for (let i = 0; i < n; i++) {
count++;
}
return count;
}
/* 阶乘阶(递归实现) */
function factorialRecur(n: number): number {
if (n == 0) return 1;
let count = 0;
// 从 1 个分裂出 n 个
for (let i = 0; i < n; i++) {
count += factorialRecur(n - 1);
}
return count;
}
/* Driver Code */
// 可以修改 n 运行,体会一下各种复杂度的操作数量变化趋势
const n = 8;
console.log("输入数据大小 n = " + n);
let count = constant(n);
console.log("常数阶的计算操作数量 = " + count);
count = linear(n);
console.log("线性阶的计算操作数量 = " + count);
count = arrayTraversal(new Array(n));
console.log("线性阶(遍历数组)的计算操作数量 = " + count);
count = quadratic(n);
console.log("平方阶的计算操作数量 = " + count);
var nums = new Array(n);
for (let i = 0; i < n; i++) nums[i] = n - i; // [n,n-1,...,2,1]
count = bubbleSort(nums);
console.log("平方阶(冒泡排序)的计算操作数量 = " + count);
count = exponential(n);
console.log("指数阶(循环实现)的计算操作数量 = " + count);
count = expRecur(n);
console.log("指数阶(递归实现)的计算操作数量 = " + count);
count = logarithmic(n);
console.log("对数阶(循环实现)的计算操作数量 = " + count);
count = logRecur(n);
console.log("对数阶(递归实现)的计算操作数量 = " + count);
count = linearLogRecur(n);
console.log("线性对数阶(递归实现)的计算操作数量 = " + count);
count = factorialRecur(n);
console.log("阶乘阶(递归实现)的计算操作数量 = " + count);

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/*
* File: worst_best_time_complexity.ts
* Created Time: 2023-01-05
* Author: RiverTwilight (contact@rene.wang)
*/
/* 生成一个数组,元素为 { 1, 2, ..., n },顺序被打乱 */
function randomNumbers(n: number): number[] {
let nums = Array(n);
// 生成数组 nums = { 1, 2, 3, ..., n }
for (let i = 0; i < n; i++) {
nums[i] = i + 1;
}
// 随机打乱数组元素
for (let i = 0; i < n; i++) {
let r = Math.floor(Math.random() * (i + 1));
let temp = nums[i];
nums[i] = nums[r];
nums[r] = temp;
}
return nums;
}
/* 查找数组 nums 中数字 1 所在索引 */
function findOne(nums: number[]): number {
for (let i = 0; i < nums.length; i++) {
if (nums[i] === 1) {
return i;
}
}
return -1;
}
/* Driver Code */
function main(): void {
for (let i = 0; i < 10; i++) {
let n = 100;
let nums = randomNumbers(n);
let index = findOne(nums);
console.log(
"\n数组 [ 1, 2, ..., n ] 被打乱后 = [" + nums.join(", ") + "]"
);
console.log("数字 1 的索引为 " + index);
}
}

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/*
/**
* File: array_hash_map.ts
* Created Time: 2022-12-20
* Author: Daniel (better.sunjian@gmail.com)

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/*
/**
* File: hash_map.ts
* Created Time: 2022-12-20
* Author: Daniel (better.sunjian@gmail.com)

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@@ -23,10 +23,10 @@ function merge(nums: number[], left: number, mid: number, right: number): void {
// 若“左子数组已全部合并完”,则选取右子数组元素,并且 j++
if (i > leftEnd) {
nums[k] = tmp[j++];
// 否则,若“右子数组已全部合并完”或“左子数组元素 < 右子数组元素”,则选取左子数组元素,并且 i++
// 否则,若“右子数组已全部合并完”或“左子数组元素 <= 右子数组元素”,则选取左子数组元素,并且 i++
} else if (j > rightEnd || tmp[i] <= tmp[j]) {
nums[k] = tmp[i++];
// 否则,若“左子数组元素 > 右子数组元素”,则选取右子数组元素,并且 j++
// 否则,若“左右子数组都未全部合并完”且“左子数组元素 > 右子数组元素”,则选取右子数组元素,并且 j++
} else {
nums[k] = tmp[j++];
}

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@@ -120,7 +120,7 @@ function remove(num: number): TreeNode | null {
// 子结点数量 = 2
else {
// 获取中序遍历中 cur 的下一个结点
let next = min(cur.right);
let next = getInOrderNext(cur.right);
let tmp = next!.val;
// 递归删除结点 nex
remove(next!.val);
@@ -130,8 +130,8 @@ function remove(num: number): TreeNode | null {
return cur;
}
/* 获取最小结点 */
function min(root: TreeNode | null): TreeNode | null {
/* 获取中序遍历中的下一个结点(仅适用于 root 有左子结点的情况) */
function getInOrderNext(root: TreeNode | null): TreeNode | null {
if (root === null) {
return null;
}

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@@ -30,7 +30,7 @@ function hierOrder(root: TreeNode | null): number[] {
/* Driver Code */
/* 初始化二叉树 */
// 这里借助了一个从数组直接生成二叉树的函数
var root = arrToTree([1, 2, 3, 4, 5, 6, 7, null, null, null, null, null, null, null, null]);
var root = arrToTree([1, 2, 3, 4, 5, 6, 7]);
console.log('\n初始化二叉树\n');
printTree(root);

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@@ -47,7 +47,7 @@ function postOrder(root: TreeNode | null): void {
/* Driver Code */
/* 初始化二叉树 */
// 这里借助了一个从数组直接生成二叉树的函数
const root = arrToTree([1, 2, 3, 4, 5, 6, 7, null, null, null, null, null, null, null, null]);
const root = arrToTree([1, 2, 3, 4, 5, 6, 7]);
console.log('\n初始化二叉树\n');
printTree(root);

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/*
/**
* File: ListNode.ts
* Created Time: 2022-12-10
* Author: Justin (xiefahit@gmail.com)

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/*
/**
* File: PrintUtil.ts
* Created Time: 2022-12-13
* Author: Justin (xiefahit@gmail.com)

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/*
/**
* File: TreeNode.ts
* Created Time: 2022-12-13
* Author: Justin (xiefahit@gmail.com)
@@ -20,7 +20,7 @@ class TreeNode {
}
/**
* Generate a binary tree with an array
* Generate a binary tree given an array
* @param arr
* @return
*/
@@ -31,19 +31,19 @@ function arrToTree(arr: (number | null)[]): TreeNode | null {
const root = new TreeNode(arr[0] as number);
const queue = [root];
let i = 1;
let i = 0;
while (queue.length) {
let node = queue.shift() as TreeNode;
if (++i >= arr.length) break;
if (arr[i] !== null) {
node.left = new TreeNode(arr[i] as number);
queue.push(node.left);
}
i++;
if (++i >= arr.length) break;
if (arr[i] !== null) {
node.right = new TreeNode(arr[i] as number);
queue.push(node.right);
}
i++;
}
return root;
}