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	feat: Add Ruby code - chapter "Sorting" (#1333)
* feat: add ruby code - chapter sorting * Update radix_sort.rb --------- Co-authored-by: Yudong Jin <krahets@163.com>
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								codes/ruby/chapter_sorting/bubble_sort.rb
									
									
									
									
									
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								codes/ruby/chapter_sorting/bubble_sort.rb
									
									
									
									
									
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					=begin
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					File: bubble_sort.rb
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					Created Time: 2024-05-02
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					Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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					=end
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					### 冒泡排序 ###
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					def bubble_sort(nums)
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					  n = nums.length
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					  # 外循环:未排序区间为 [0, i]
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					  for i in (n - 1).downto(1)
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					    # 内循环:将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
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					    for j in 0...i
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					      if nums[j] > nums[j + 1]
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					        # 交换 nums[j] 与 nums[j + 1]
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					        nums[j], nums[j + 1] = nums[j + 1], nums[j]
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					      end
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					    end
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					  end
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					end
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					### 冒泡排序(标志优化)###
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					def bubble_sort_with_flag(nums)
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					  n = nums.length
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					  # 外循环:未排序区间为 [0, i]
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					  for i in (n - 1).downto(1)
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					    flag = false # 初始化标志位
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					    # 内循环:将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
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					    for j in 0...i
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					      if nums[j] > nums[j + 1]
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					        # 交换 nums[j] 与 nums[j + 1]
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					        nums[j], nums[j + 1] = nums[j + 1], nums[j]
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					        flag = true # 记录交换元素
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					      end
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					    end
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					    break unless flag # 此轮“冒泡”未交换任何元素,直接跳出
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					  end
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					end
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					### Driver Code ###
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					if __FILE__ == $0
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					  nums = [4, 1, 3, 1, 5, 2]
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					  bubble_sort(nums)
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					  puts "冒泡排序完成后 nums = #{nums}"
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					  nums1 = [4, 1, 3, 1, 5, 2]
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					  bubble_sort_with_flag(nums1)
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					  puts "冒泡排序完成后 nums = #{nums1}"
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					end
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										62
									
								
								codes/ruby/chapter_sorting/counting_sort.rb
									
									
									
									
									
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								codes/ruby/chapter_sorting/counting_sort.rb
									
									
									
									
									
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					=begin
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					File: counting_sort.rb
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					Created Time: 2024-05-02
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					Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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					=end
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					### 计数排序 ###
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					def counting_sort_naive(nums)
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					  # 简单实现,无法用于排序对象
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					  # 1. 统计数组最大元素 m
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					  m = 0
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					  nums.each { |num| m = [m, num].max }
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					  # 2. 统计各数字的出现次数
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					  # counter[num] 代表 num 的出现次数
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					  counter = Array.new(m + 1, 0)
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					  nums.each { |num| counter[num] += 1 }
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					  # 3. 遍历 counter ,将各元素填入原数组 nums
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					  i = 0
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					  for num in 0...(m + 1)
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					    (0...counter[num]).each do
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					      nums[i] = num
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					      i += 1
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					    end
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					  end
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					end
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					### 计数排序 ###
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					def counting_sort(nums)
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					  # 完整实现,可排序对象,并且是稳定排序
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					  # 1. 统计数组最大元素 m
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					  m = nums.max
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					  # 2. 统计各数字的出现次数
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					  # counter[num] 代表 num 的出现次数
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					  counter = Array.new(m + 1, 0)
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					  nums.each { |num| counter[num] += 1 }
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					  # 3. 求 counter 的前缀和,将“出现次数”转换为“尾索引”
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					  # 即 counter[num]-1 是 num 在 res 中最后一次出现的索引
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					  (0...m).each { |i| counter[i + 1] += counter[i] }
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					  # 4. 倒序遍历 nums, 将各元素填入结果数组 res
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					  # 初始化数组 res 用于记录结果
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					  n = nums.length
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					  res = Array.new(n, 0)
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					  (n - 1).downto(0).each do |i|
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					    num = nums[i]
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					    res[counter[num] - 1] = num # 将 num 放置到对应索引处
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					    counter[num] -= 1 # 令前缀和自减 1 ,得到下次放置 num 的索引
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					  end
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					  # 使用结果数组 res 覆盖原数组 nums
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					  (0...n).each { |i| nums[i] = res[i] }
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					end
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					### Driver Code ###
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					if __FILE__ == $0
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					  nums = [1, 0, 1, 2, 0, 4, 0, 2, 2, 4]
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					  counting_sort_naive(nums)
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					  puts "计数排序(无法排序对象)完成后 nums = #{nums}"
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					  nums1 = [1, 0, 1, 2, 0, 4, 0, 2, 2, 4]
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					  counting_sort(nums1)
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					  puts "计数排序完成后 nums1 = #{nums1}"
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					end
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										70
									
								
								codes/ruby/chapter_sorting/radix_sort.rb
									
									
									
									
									
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								codes/ruby/chapter_sorting/radix_sort.rb
									
									
									
									
									
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					=begin
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					File: radix_sort.rb
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					Created Time: 2024-05-03
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					Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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					=end
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					### 获取元素 num 的第 k 位,其中 exp = 10^(k-1) ###
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					def digit(num, exp)
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					  # 转入 exp 而非 k 可以避免在此重复执行昂贵的次方计算
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					  (num / exp) % 10
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					end
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					### 计数排序(根据 nums 第 k 位排序)###
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					def counting_sort_digit(nums, exp)
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					  # 十进制的位范围为 0~9 ,因此需要长度为 10 的桶数组
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					  counter = Array.new(10, 0)
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					  n = nums.length
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					  # 统计 0~9 各数字的出现次数
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					  for i in 0...n
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					    d = digit(nums[i], exp) # 获取 nums[i] 第 k 位,记为 d
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					    counter[d] += 1 # 统计数字 d 的出现次数
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					  end
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					  # 求前缀和,将“出现个数”转换为“数组索引”
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					  (1...10).each { |i| counter[i] += counter[i - 1] }
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					  # 倒序遍历,根据桶内统计结果,将各元素填入 res
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					  res = Array.new(n, 0)
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					  for i in (n - 1).downto(0)
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					    d = digit(nums[i], exp)
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					    j = counter[d] - 1 # 获取 d 在数组中的索引 j
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					    res[j] = nums[i] # 将当前元素填入索引 j
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					    counter[d] -= 1 # 将 d 的数量减 1
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					  end
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					  # 使用结果覆盖原数组 nums
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					  (0...n).each { |i| nums[i] = res[i] }
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					end
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					### 基数排序 ###
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					def radix_sort(nums)
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					  # 获取数组的最大元素,用于判断最大位数
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					  m = nums.max
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					  # 按照从低位到高位的顺序遍历
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					  exp = 1
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					  while exp <= m
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					    # 对数组元素的第 k 位执行计数排序
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					    # k = 1 -> exp = 1
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					    # k = 2 -> exp = 10
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					    # 即 exp = 10^(k-1)
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					    counting_sort_digit(nums, exp)
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					    exp *= 10
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					  end
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					end
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					### Driver Code ###
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					if __FILE__ == $0
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					  # 基数排序
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					  nums = [
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					    10546151,
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					    35663510,
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					    42865989,
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					    34862445,
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					    81883077,
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					    88906420,
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					    72429244,
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					    30524779,
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					    82060337,
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					    63832996,
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					  ]
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					  radix_sort(nums)
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					  puts "基数排序完成后 nums = #{nums}"
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					end
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										29
									
								
								codes/ruby/chapter_sorting/selection_sort.rb
									
									
									
									
									
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								codes/ruby/chapter_sorting/selection_sort.rb
									
									
									
									
									
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					=begin
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					File: selection_sort.rb
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					Created Time: 2024-05-03
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					Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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					=end
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					### 选择排序 ###
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					def selection_sort(nums)
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					  n = nums.length
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					  # 外循环:未排序区间为 [i, n-1]
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					  for i in 0...(n - 1)
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					    # 内循环:找到未排序区间内的最小元素
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					    k = i
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					    for j in (i + 1)...n
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					      if nums[j] < nums[k]
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					        k = j # 记录最小元素的索引
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					      end
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					    end
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					    # 将该最小元素与未排序区间的首个元素交换
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					    nums[i], nums[k] = nums[k], nums[i]
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					  end
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					end
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					### Driver Code ###
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					if __FILE__ == $0
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					  nums = [4, 1, 3, 1, 5, 2]
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					  selection_sort(nums)
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					  puts "选择排序完成后 nums = #{nums}"
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					end
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