mirror of
https://github.com/krahets/hello-algo.git
synced 2025-11-02 12:58:42 +08:00
Bug fixes and improvements (#1348)
* Add "reference" for EN version. Bug fixes. * Unify the figure reference as "the figure below" and "the figure above". Bug fixes. * Format the EN markdown files. * Replace "" with <u></u> for EN version and bug fixes * Fix biary_tree_dfs.png * Fix biary_tree_dfs.png * Fix zh-hant/biary_tree_dfs.png * Fix heap_sort_step1.png * Sync zh and zh-hant versions. * Bug fixes * Fix EN figures * Bug fixes * Fix the figure labels for EN version
This commit is contained in:
51
zh-hant/codes/ruby/chapter_sorting/bubble_sort.rb
Normal file
51
zh-hant/codes/ruby/chapter_sorting/bubble_sort.rb
Normal file
@ -0,0 +1,51 @@
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=begin
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File: bubble_sort.rb
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Created Time: 2024-05-02
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Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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=end
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### 泡沫排序 ###
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def bubble_sort(nums)
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n = nums.length
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# 外迴圈:未排序區間為 [0, i]
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for i in (n - 1).downto(1)
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# 內迴圈:將未排序區間 [0, i] 中的最大元素交換至該區間的最右端
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for j in 0...i
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if nums[j] > nums[j + 1]
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# 交換 nums[j] 與 nums[j + 1]
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nums[j], nums[j + 1] = nums[j + 1], nums[j]
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end
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end
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end
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end
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### 泡沫排序(標誌最佳化)###
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def bubble_sort_with_flag(nums)
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n = nums.length
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# 外迴圈:未排序區間為 [0, i]
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for i in (n - 1).downto(1)
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flag = false # 初始化標誌位
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# 內迴圈:將未排序區間 [0, i] 中的最大元素交換至該區間的最右端
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for j in 0...i
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if nums[j] > nums[j + 1]
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# 交換 nums[j] 與 nums[j + 1]
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nums[j], nums[j + 1] = nums[j + 1], nums[j]
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flag = true # 記錄交換元素
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end
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end
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break unless flag # 此輪“冒泡”未交換任何元素,直接跳出
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end
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end
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### Driver Code ###
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if __FILE__ == $0
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nums = [4, 1, 3, 1, 5, 2]
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bubble_sort(nums)
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puts "泡沫排序完成後 nums = #{nums}"
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nums1 = [4, 1, 3, 1, 5, 2]
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bubble_sort_with_flag(nums1)
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puts "泡沫排序完成後 nums = #{nums1}"
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end
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43
zh-hant/codes/ruby/chapter_sorting/bucket_sort.rb
Normal file
43
zh-hant/codes/ruby/chapter_sorting/bucket_sort.rb
Normal file
@ -0,0 +1,43 @@
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=begin
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File: bucket_sort.rb
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Created Time: 2024-04-17
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Author: Martin Xu (martin.xus@gmail.com)
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=end
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### 桶排序 ###
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def bucket_sort(nums)
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# 初始化 k = n/2 個桶,預期向每個桶分配 2 個元素
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k = nums.length / 2
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buckets = Array.new(k) { [] }
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# 1. 將陣列元素分配到各個桶中
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nums.each do |num|
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# 輸入資料範圍為 [0, 1),使用 num * k 對映到索引範圍 [0, k-1]
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i = (num * k).to_i
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# 將 num 新增進桶 i
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buckets[i] << num
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end
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# 2. 對各個桶執行排序
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buckets.each do |bucket|
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# 使用內建排序函式,也可以替換成其他排序演算法
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bucket.sort!
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end
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# 3. 走訪桶合併結果
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i = 0
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buckets.each do |bucket|
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bucket.each do |num|
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nums[i] = num
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i += 1
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end
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end
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end
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### Driver Code ###
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if __FILE__ == $0
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# 設輸入資料為浮點數,範圍為 [0, 1)
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nums = [0.49, 0.96, 0.82, 0.09, 0.57, 0.43, 0.91, 0.75, 0.15, 0.37]
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bucket_sort(nums)
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puts "桶排序完成後 nums = #{nums}"
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end
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62
zh-hant/codes/ruby/chapter_sorting/counting_sort.rb
Normal file
62
zh-hant/codes/ruby/chapter_sorting/counting_sort.rb
Normal file
@ -0,0 +1,62 @@
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=begin
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File: counting_sort.rb
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Created Time: 2024-05-02
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Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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=end
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### 計數排序 ###
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def counting_sort_naive(nums)
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# 簡單實現,無法用於排序物件
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# 1. 統計陣列最大元素 m
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m = 0
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nums.each { |num| m = [m, num].max }
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# 2. 統計各數字的出現次數
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# counter[num] 代表 num 的出現次數
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counter = Array.new(m + 1, 0)
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nums.each { |num| counter[num] += 1 }
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# 3. 走訪 counter ,將各元素填入原陣列 nums
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i = 0
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for num in 0...(m + 1)
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(0...counter[num]).each do
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nums[i] = num
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i += 1
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end
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end
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end
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### 計數排序 ###
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def counting_sort(nums)
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# 完整實現,可排序物件,並且是穩定排序
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# 1. 統計陣列最大元素 m
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m = nums.max
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# 2. 統計各數字的出現次數
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# counter[num] 代表 num 的出現次數
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counter = Array.new(m + 1, 0)
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nums.each { |num| counter[num] += 1 }
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# 3. 求 counter 的前綴和,將“出現次數”轉換為“尾索引”
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# 即 counter[num]-1 是 num 在 res 中最後一次出現的索引
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(0...m).each { |i| counter[i + 1] += counter[i] }
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# 4. 倒序走訪 nums, 將各元素填入結果陣列 res
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# 初始化陣列 res 用於記錄結果
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n = nums.length
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res = Array.new(n, 0)
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(n - 1).downto(0).each do |i|
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num = nums[i]
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res[counter[num] - 1] = num # 將 num 放置到對應索引處
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counter[num] -= 1 # 令前綴和自減 1 ,得到下次放置 num 的索引
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end
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# 使用結果陣列 res 覆蓋原陣列 nums
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(0...n).each { |i| nums[i] = res[i] }
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end
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### Driver Code ###
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if __FILE__ == $0
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nums = [1, 0, 1, 2, 0, 4, 0, 2, 2, 4]
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counting_sort_naive(nums)
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puts "計數排序(無法排序物件)完成後 nums = #{nums}"
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nums1 = [1, 0, 1, 2, 0, 4, 0, 2, 2, 4]
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counting_sort(nums1)
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puts "計數排序完成後 nums1 = #{nums1}"
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end
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45
zh-hant/codes/ruby/chapter_sorting/heap_sort.rb
Normal file
45
zh-hant/codes/ruby/chapter_sorting/heap_sort.rb
Normal file
@ -0,0 +1,45 @@
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=begin
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File: heap_sort.rb
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Created Time: 2024-04-10
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Author: junminhong (junminhong1110@gmail.com)
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=end
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### 堆積的長度為 n ,從節點 i 開始,從頂至底堆積化 ###
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def sift_down(nums, n, i)
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while true
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# 判斷節點 i, l, r 中值最大的節點,記為 ma
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l = 2 * i + 1
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r = 2 * i + 2
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ma = i
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ma = l if l < n && nums[l] > nums[ma]
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ma = r if r < n && nums[r] > nums[ma]
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# 若節點 i 最大或索引 l, r 越界,則無須繼續堆積化,跳出
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break if ma == i
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# 交換兩節點
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nums[i], nums[ma] = nums[ma], nums[i]
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# 迴圈向下堆積化
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i = ma
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end
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end
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### 堆積排序 ###
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def heap_sort(nums)
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# 建堆積操作:堆積化除葉節點以外的其他所有節點
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(nums.length / 2 - 1).downto(0) do |i|
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sift_down(nums, nums.length, i)
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end
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# 從堆積中提取最大元素,迴圈 n-1 輪
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(nums.length - 1).downto(1) do |i|
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# 交換根節點與最右葉節點(交換首元素與尾元素)
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nums[0], nums[i] = nums[i], nums[0]
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# 以根節點為起點,從頂至底進行堆積化
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sift_down(nums, i, 0)
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end
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end
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### Driver Code ###
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if __FILE__ == $0
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nums = [4, 1, 3, 1, 5, 2]
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heap_sort(nums)
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puts "堆積排序完成後 nums = #{nums.inspect}"
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end
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60
zh-hant/codes/ruby/chapter_sorting/merge_sort.rb
Normal file
60
zh-hant/codes/ruby/chapter_sorting/merge_sort.rb
Normal file
@ -0,0 +1,60 @@
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=begin
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File: merge_sort.rb
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Created Time: 2024-04-10
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Author: junminhong (junminhong1110@gmail.com)
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=end
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### 合併左子陣列和右子陣列 ###
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def merge(nums, left, mid, right)
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# 左子陣列區間為 [left, mid], 右子陣列區間為 [mid+1, right]
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# 建立一個臨時陣列 tmp,用於存放合併後的結果
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tmp = Array.new(right - left + 1, 0)
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# 初始化左子陣列和右子陣列的起始索引
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i, j, k = left, mid + 1, 0
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# 當左右子陣列都還有元素時,進行比較並將較小的元素複製到臨時陣列中
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while i <= mid && j <= right
|
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if nums[i] <= nums[j]
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tmp[k] = nums[i]
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i += 1
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else
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tmp[k] = nums[j]
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j += 1
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end
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k += 1
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end
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# 將左子陣列和右子陣列的剩餘元素複製到臨時陣列中
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||||
while i <= mid
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||||
tmp[k] = nums[i]
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i += 1
|
||||
k += 1
|
||||
end
|
||||
while j <= right
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||||
tmp[k] = nums[j]
|
||||
j += 1
|
||||
k += 1
|
||||
end
|
||||
# 將臨時陣列 tmp 中的元素複製回原陣列 nums 的對應區間
|
||||
(0...tmp.length).each do |k|
|
||||
nums[left + k] = tmp[k]
|
||||
end
|
||||
end
|
||||
|
||||
### 合併排序 ###
|
||||
def merge_sort(nums, left, right)
|
||||
# 終止條件
|
||||
# 當子陣列長度為 1 時終止遞迴
|
||||
return if left >= right
|
||||
# 劃分階段
|
||||
mid = (left + right) / 2 # 計算中點
|
||||
merge_sort(nums, left, mid) # 遞迴左子陣列
|
||||
merge_sort(nums, mid + 1, right) # 遞迴右子陣列
|
||||
# 合併階段
|
||||
merge(nums, left, mid, right)
|
||||
end
|
||||
|
||||
### Driver Code ###
|
||||
if __FILE__ == $0
|
||||
nums = [7, 3, 2, 6, 0, 1, 5, 4]
|
||||
merge_sort(nums, 0, nums.length - 1)
|
||||
puts "合併排序完成後 nums = #{nums.inspect}"
|
||||
end
|
||||
@ -9,7 +9,6 @@ class QuickSort
|
||||
class << self
|
||||
### 哨兵劃分 ###
|
||||
def partition(nums, left, right)
|
||||
|
||||
# 以 nums[left] 為基準數
|
||||
i, j = left, right
|
||||
while i < j
|
||||
@ -116,7 +115,7 @@ class QuickSortTailCall
|
||||
i # 返回基準數的索引
|
||||
end
|
||||
|
||||
### 快速排序(尾遞迴最佳化)
|
||||
### 快速排序(尾遞迴最佳化)###
|
||||
def quick_sort(nums, left, right)
|
||||
# 子陣列長度不為 1 時遞迴
|
||||
while left < right
|
||||
|
||||
70
zh-hant/codes/ruby/chapter_sorting/radix_sort.rb
Normal file
70
zh-hant/codes/ruby/chapter_sorting/radix_sort.rb
Normal file
@ -0,0 +1,70 @@
|
||||
=begin
|
||||
File: radix_sort.rb
|
||||
Created Time: 2024-05-03
|
||||
Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
|
||||
=end
|
||||
|
||||
### 獲取元素 num 的第 k 位,其中 exp = 10^(k-1) ###
|
||||
def digit(num, exp)
|
||||
# 轉入 exp 而非 k 可以避免在此重複執行昂貴的次方計算
|
||||
(num / exp) % 10
|
||||
end
|
||||
|
||||
### 計數排序(根據 nums 第 k 位排序)###
|
||||
def counting_sort_digit(nums, exp)
|
||||
# 十進位制的位範圍為 0~9 ,因此需要長度為 10 的桶陣列
|
||||
counter = Array.new(10, 0)
|
||||
n = nums.length
|
||||
# 統計 0~9 各數字的出現次數
|
||||
for i in 0...n
|
||||
d = digit(nums[i], exp) # 獲取 nums[i] 第 k 位,記為 d
|
||||
counter[d] += 1 # 統計數字 d 的出現次數
|
||||
end
|
||||
# 求前綴和,將“出現個數”轉換為“陣列索引”
|
||||
(1...10).each { |i| counter[i] += counter[i - 1] }
|
||||
# 倒序走訪,根據桶內統計結果,將各元素填入 res
|
||||
res = Array.new(n, 0)
|
||||
for i in (n - 1).downto(0)
|
||||
d = digit(nums[i], exp)
|
||||
j = counter[d] - 1 # 獲取 d 在陣列中的索引 j
|
||||
res[j] = nums[i] # 將當前元素填入索引 j
|
||||
counter[d] -= 1 # 將 d 的數量減 1
|
||||
end
|
||||
# 使用結果覆蓋原陣列 nums
|
||||
(0...n).each { |i| nums[i] = res[i] }
|
||||
end
|
||||
|
||||
### 基數排序 ###
|
||||
def radix_sort(nums)
|
||||
# 獲取陣列的最大元素,用於判斷最大位數
|
||||
m = nums.max
|
||||
# 按照從低位到高位的順序走訪
|
||||
exp = 1
|
||||
while exp <= m
|
||||
# 對陣列元素的第 k 位執行計數排序
|
||||
# k = 1 -> exp = 1
|
||||
# k = 2 -> exp = 10
|
||||
# 即 exp = 10^(k-1)
|
||||
counting_sort_digit(nums, exp)
|
||||
exp *= 10
|
||||
end
|
||||
end
|
||||
|
||||
### Driver Code ###
|
||||
if __FILE__ == $0
|
||||
# 基數排序
|
||||
nums = [
|
||||
10546151,
|
||||
35663510,
|
||||
42865989,
|
||||
34862445,
|
||||
81883077,
|
||||
88906420,
|
||||
72429244,
|
||||
30524779,
|
||||
82060337,
|
||||
63832996,
|
||||
]
|
||||
radix_sort(nums)
|
||||
puts "基數排序完成後 nums = #{nums}"
|
||||
end
|
||||
29
zh-hant/codes/ruby/chapter_sorting/selection_sort.rb
Normal file
29
zh-hant/codes/ruby/chapter_sorting/selection_sort.rb
Normal file
@ -0,0 +1,29 @@
|
||||
=begin
|
||||
File: selection_sort.rb
|
||||
Created Time: 2024-05-03
|
||||
Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
|
||||
=end
|
||||
|
||||
### 選擇排序 ###
|
||||
def selection_sort(nums)
|
||||
n = nums.length
|
||||
# 外迴圈:未排序區間為 [i, n-1]
|
||||
for i in 0...(n - 1)
|
||||
# 內迴圈:找到未排序區間內的最小元素
|
||||
k = i
|
||||
for j in (i + 1)...n
|
||||
if nums[j] < nums[k]
|
||||
k = j # 記錄最小元素的索引
|
||||
end
|
||||
end
|
||||
# 將該最小元素與未排序區間的首個元素交換
|
||||
nums[i], nums[k] = nums[k], nums[i]
|
||||
end
|
||||
end
|
||||
|
||||
### Driver Code ###
|
||||
if __FILE__ == $0
|
||||
nums = [4, 1, 3, 1, 5, 2]
|
||||
selection_sort(nums)
|
||||
puts "選擇排序完成後 nums = #{nums}"
|
||||
end
|
||||
Reference in New Issue
Block a user