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<p>注意，数组可能不包含目标元素 <code>target</code> 。因此在函数返回前，我们需要先判断 <code>nums[i]</code> 与 <code>target</code> 是否相等，以及索引 <span class="arithmatex">\(i\)</span> 是否越界。</p>
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<div class="highlight"><span class="filename">binary_search_edge.java</span><pre><span></span><code><a id="__codelineno-0-1" name="__codelineno-0-1" href="#__codelineno-0-1"></a><span class="cm">/* 二分查找最左一个元素 */</span>
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<h2 id="1023">10.2.3. &nbsp; 查找右边界<a class="headerlink" href="#1023" title="Permanent link">&para;</a></h2>
<p>类似地，我们也可以二分查找最右边的 <code>target</code> 。当 <code>nums[m] == target</code> 时，说明大于 <code>target</code> 的元素在区间 <span class="arithmatex">\([m + 1, j]\)</span> 中，因此执行 <code>i = m + 1</code> ，<strong>使得指针 <span class="arithmatex">\(i\)</span> 向大于 <code>target</code> 的元素靠近</strong>。</p>
<p>完成二分后，<strong><span class="arithmatex">\(i\)</span> 指向首个大于 <code>target</code> 的元素，<span class="arithmatex">\(j\)</span> 指向最右边的 <code>target</code></strong> ，因此返回索引 <span class="arithmatex">\(j\)</span> 即可。</p>
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<div class="highlight"><span class="filename">binary_search_edge.java</span><pre><span></span><code><a id="__codelineno-12-1" name="__codelineno-12-1" href="#__codelineno-12-1"></a><span class="cm">/* 二分查找最右一个元素 */</span>