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Update the section of intro to DP.
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/**
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* File: climbing_stairs_constraint_dp.cpp
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* Created Time: 2023-07-01
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* Author: Krahets (krahets@163.com)
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*/
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#include "../utils/common.hpp"
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/* 带约束爬楼梯:动态规划 */
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int climbingStairsConstraintDP(int n) {
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if (n == 1 || n == 2) {
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return n;
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}
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// 初始化 dp 列表,用于存储子问题的解
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vector<vector<int>> dp(n + 1, vector<int>(3, 0));
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// 初始状态:预设最小子问题的解
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dp[1][1] = 1;
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dp[1][2] = 0;
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dp[2][1] = 0;
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dp[2][2] = 1;
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// 状态转移:从较小子问题逐步求解较大子问题
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for (int i = 3; i <= n; i++) {
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dp[i][1] = dp[i - 1][2];
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dp[i][2] = dp[i - 2][1] + dp[i - 2][2];
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}
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return dp[n][1] + dp[n][2];
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}
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/* Driver Code */
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int main() {
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int n = 9;
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int res = climbingStairsConstraintDP(n);
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cout << "爬 " << n << " 阶楼梯共有 " << res << " 种方案" << endl;
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return 0;
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}
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/**
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* File: climbing_stairs_constraint_dp.java
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* Created Time: 2023-07-01
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* Author: Krahets (krahets@163.com)
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*/
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package chapter_dynamic_programming;
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public class climbing_stairs_constraint_dp {
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/* 带约束爬楼梯:动态规划 */
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static int climbingStairsConstraintDP(int n) {
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if (n == 1 || n == 2) {
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return n;
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}
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// 初始化 dp 列表,用于存储子问题的解
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int[][] dp = new int[n + 1][3];
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// 初始状态:预设最小子问题的解
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dp[1][1] = 1;
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dp[1][2] = 0;
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dp[2][1] = 0;
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dp[2][2] = 1;
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// 状态转移:从较小子问题逐步求解较大子问题
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for (int i = 3; i <= n; i++) {
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dp[i][1] = dp[i - 1][2];
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dp[i][2] = dp[i - 2][1] + dp[i - 2][2];
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}
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return dp[n][1] + dp[n][2];
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}
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public static void main(String[] args) {
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int n = 9;
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int res = climbingStairsConstraintDP(n);
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System.out.println(String.format("爬 %d 阶楼梯共有 %d 种方案", n, res));
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}
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}
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"""
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File: climbing_stairs_constraint_dp.py
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Created Time: 2023-06-30
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Author: Krahets (krahets@163.com)
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"""
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def climbing_stairs_constraint_dp(n: int) -> int:
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"""带约束爬楼梯:动态规划"""
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if n == 1 or n == 2:
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return n
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# 初始化 dp 列表,用于存储子问题的解
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dp = [[0] * 3 for _ in range(n + 1)]
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# 初始状态:预设最小子问题的解
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dp[1][1], dp[1][2] = 1, 0
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dp[2][1], dp[2][2] = 0, 1
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# 状态转移:从较小子问题逐步求解较大子问题
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for i in range(3, n + 1):
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dp[i][1] = dp[i - 1][2]
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dp[i][2] = dp[i - 2][1] + dp[i - 2][2]
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return dp[n][1] + dp[n][2]
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"""Driver Code"""
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if __name__ == "__main__":
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n = 9
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res = climbing_stairs_constraint_dp(n)
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print(f"爬 {n} 阶楼梯共有 {res} 种方案")
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