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refactor: Follow the PEP 585 Typing standard (#439)

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* Follow the PEP 585 Typing standard

* Update list.py
This commit is contained in:
Yudong Jin
2023-03-23 18:51:56 +08:00
committed by GitHub
parent f4e01ea32e
commit 8918ec9079
43 changed files with 256 additions and 342 deletions
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10
codes/python/chapter_computational_complexity/time_complexity.py
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@ -4,10 +4,6 @@ Created Time: 2022-11-25
Author: Krahets (krahets@163.com)
"""
import sys, os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
from modules import *
def constant(n: int) -> int:
""" 常数阶 """
count: int = 0
@ -23,7 +19,7 @@ def linear(n: int) -> int:
count += 1
return count
def array_traversal(nums: List[int]) -> int:
def array_traversal(nums: list[int]) -> int:
""" 线性阶（遍历数组）"""
count: int = 0
# 循环次数与数组长度成正比
@ -40,7 +36,7 @@ def quadratic(n: int) -> int:
count += 1
return count
def bubble_sort(nums: List[int]) -> int:
def bubble_sort(nums: list[int]) -> int:
""" 平方阶（冒泡排序）"""
count: int = 0 # 计数器
# 外循环：待排序元素数量为 n-1, n-2, ..., 1
@ -120,7 +116,7 @@ if __name__ == "__main__":
count: int = quadratic(n)
print("平方阶的计算操作数量 =", count)
nums: List[int] = [i for i in range(n, 0, -1)] # [n,n-1,...,2,1]
nums: list[int] = [i for i in range(n, 0, -1)] # [n,n-1,...,2,1]
count: int = bubble_sort(nums)
print("平方阶（冒泡排序）的计算操作数量 =", count)