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	feat(csharp/backtracking): add csharp code in n queens (#485)
* feat(csharp/backtracking): add csharp code in n queens * fix format * Update n_queens.cs --------- Co-authored-by: Yudong Jin <krahets@163.com>
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								codes/csharp/chapter_backtracking/n_queens.cs
									
									
									
									
									
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					/**
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					 * File: n_queens.cs
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					 * Created Time: 2023-05-04
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					 * Author: hpstory (hpstory1024@163.com)
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					 */
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					using hello_algo.utils;
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					using NUnit.Framework;
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					namespace hello_algo.chapter_backtracking;
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					public class n_queens {
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					    /* 回溯算法:N 皇后 */
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					    static void backtrack(int row, int n, List<List<string>> state, List<List<List<string>>> res,
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					            bool[] cols, bool[] diags1, bool[] diags2) {
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					        // 当放置完所有行时,记录解
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					        if (row == n) {
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					            List<List<string>> copyState = new List<List<string>>();
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					            foreach (List<string> sRow in state) {
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					                copyState.Add(new List<string>(sRow));
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					            }
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					            res.Add(copyState);
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					            return;
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					        }
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					        // 遍历所有列
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					        for (int col = 0; col < n; col++) {
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					            // 计算该格子对应的主对角线和副对角线
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					            int diag1 = row - col + n - 1;
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					            int diag2 = row + col;
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					            // 剪枝:不允许该格子所在 (列 或 主对角线 或 副对角线) 包含皇后
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					            if (!(cols[col] || diags1[diag1] || diags2[diag2])) {
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					                // 尝试:将皇后放置在该格子
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					                state[row][col] = "Q";
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					                cols[col] = diags1[diag1] = diags2[diag2] = true;
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					                // 放置下一行
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					                backtrack(row + 1, n, state, res, cols, diags1, diags2);
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					                // 回退:将该格子恢复为空位
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					                state[row][col] = "#";
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					                cols[col] = diags1[diag1] = diags2[diag2] = false;
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					            }
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					        }
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					    }
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					    /* 求解 N 皇后 */
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					    static List<List<List<string>>> nQueens(int n) {
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					        // 初始化 n*n 大小的棋盘,其中 'Q' 代表皇后,'#' 代表空位
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					        List<List<string>> state = new List<List<string>>();
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					        for (int i = 0; i < n; i++) {
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					            List<string> row = new List<string>();
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					            for (int j = 0; j < n; j++) {
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					                row.Add("#");
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					            }
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					            state.Add(row);
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					        }
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					        bool[] cols = new bool[n]; // 记录列是否有皇后
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					        bool[] diags1 = new bool[2 * n - 1]; // 记录主对角线是否有皇后
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					        bool[] diags2 = new bool[2 * n - 1]; // 记录副对角线是否有皇后
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					        List<List<List<string>>> res = new List<List<List<string>>>();
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					        backtrack(0, n, state, res, cols, diags1, diags2);
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					        return res;
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					    }
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					    [Test]
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					    public void Test() {
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					        int n = 4;
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					        List<List<List<string>>> res = nQueens(n);
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					        Console.WriteLine("输入棋盘长宽为 " + n);
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					        Console.WriteLine("皇后放置方案共有 " + res.Count + " 种");
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					        foreach (List<List<string>> state in res) {
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					            Console.WriteLine("--------------------");
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					            foreach (List<string> row in state) {
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					                PrintUtil.PrintList(row);
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					            }
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					        }
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					    }
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					}
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