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Add the section of binary search insertion. (#671)
Refactor the section of binary search edge. Finetune the figures of binary search.
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@@ -1,51 +1,48 @@
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"""
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File: binary_search_edge.py
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Created Time: 2023-05-18
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Created Time: 2023-08-04
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Author: Krahets (krahets@163.com)
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"""
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import sys, os.path as osp
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sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
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from binary_search_insertion import binary_search_insertion
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def binary_search_left_edge(nums: list[int], target: int) -> int:
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"""二分查找最左一个元素"""
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i, j = 0, len(nums) - 1 # 初始化双闭区间 [0, n-1]
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while i <= j:
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m = (i + j) // 2 # 计算中点索引 m
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if nums[m] < target:
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i = m + 1 # target 在区间 [m+1, j] 中
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elif nums[m] > target:
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j = m - 1 # target 在区间 [i, m-1] 中
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else:
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j = m - 1 # 首个小于 target 的元素在区间 [i, m-1] 中
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"""二分查找最左一个 target"""
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# 等价于查找 target 的插入点
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i = binary_search_insertion(nums, target)
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# 未找到 target ,返回 -1
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if i == len(nums) or nums[i] != target:
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return -1 # 未找到目标元素,返回 -1
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return -1
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# 找到 target ,返回索引 i
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return i
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def binary_search_right_edge(nums: list[int], target: int) -> int:
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"""二分查找最右一个元素"""
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i, j = 0, len(nums) - 1 # 初始化双闭区间 [0, n-1]
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while i <= j:
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m = (i + j) // 2 # 计算中点索引 m
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if nums[m] < target:
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i = m + 1 # target 在区间 [m+1, j] 中
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elif nums[m] > target:
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j = m - 1 # target 在区间 [i, m-1] 中
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else:
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i = m + 1 # 首个大于 target 的元素在区间 [m+1, j] 中
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if j < 0 or nums[j] != target:
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return -1 # 未找到目标元素,返回 -1
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"""二分查找最右一个 target"""
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# 转化为查找最左一个 target + 1
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i = binary_search_insertion(nums, target + 1)
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# j 指向最右一个 target ,i 指向首个大于 target 的元素
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j = i - 1
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# 未找到 target ,返回 -1
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if j == -1 or nums[j] != target:
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return -1
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# 找到 target ,返回索引 j
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return j
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"""Driver Code"""
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if __name__ == "__main__":
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target = 6
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# 包含重复元素的数组
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nums = [1, 3, 6, 6, 6, 6, 6, 10, 12, 15]
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print(f"\n数组 nums = {nums}")
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# 二分查找最左一个元素
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index_left = binary_search_left_edge(nums, target)
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print("数组中最左一个元素 6 的索引 = ", index_left)
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# 二分查找最右一个元素
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index_right = binary_search_right_edge(nums, target)
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print("数组中最右一个元素 6 的索引 = ", index_right)
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# 二分查找左边界和右边界
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for target in [6, 7]:
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index = binary_search_left_edge(nums, target)
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print(f"最左一个元素 {target} 的索引为 {index}")
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index = binary_search_right_edge(nums, target)
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print(f"最右一个元素 {target} 的索引为 {index}")
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54
codes/python/chapter_searching/binary_search_insertion.py
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54
codes/python/chapter_searching/binary_search_insertion.py
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@@ -0,0 +1,54 @@
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"""
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File: binary_search_insertion.py
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Created Time: 2023-08-04
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Author: Krahets (krahets@163.com)
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"""
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def binary_search_insertion_simple(nums: list[int], target: int) -> int:
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"""二分查找插入点(无重复元素)"""
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i, j = 0, len(nums) - 1 # 初始化双闭区间 [0, n-1]
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while i <= j:
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m = (i + j) // 2 # 计算中点索引 m
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if nums[m] < target:
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i = m + 1 # target 在区间 [m+1, j] 中
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elif nums[m] > target:
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j = m - 1 # target 在区间 [i, m-1] 中
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else:
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return m # 找到 target ,返回插入点 m
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# 未找到 target ,返回插入点 i
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return i
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def binary_search_insertion(nums: list[int], target: int) -> int:
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"""二分查找插入点(存在重复元素)"""
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i, j = 0, len(nums) - 1 # 初始化双闭区间 [0, n-1]
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while i <= j:
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m = (i + j) // 2 # 计算中点索引 m
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if nums[m] < target:
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i = m + 1 # target 在区间 [m+1, j] 中
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elif nums[m] > target:
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j = m - 1 # target 在区间 [i, m-1] 中
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else:
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j = m - 1 # 首个小于 target 的元素在区间 [i, m-1] 中
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# 返回插入点 i
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return i
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"""Driver Code"""
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if __name__ == "__main__":
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# 无重复元素的数组
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nums = [1, 3, 6, 8, 12, 15, 23, 26, 31, 35]
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print(f"\n数组 nums = {nums}")
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# 二分查找插入点
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for target in [6, 9]:
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index = binary_search_insertion_simple(nums, target)
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print(f"元素 {target} 的插入点的索引为 {index}")
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# 包含重复元素的数组
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nums = [1, 3, 6, 6, 6, 6, 6, 10, 12, 15]
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print(f"\n数组 nums = {nums}")
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# 二分查找插入点
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for target in [2, 6, 20]:
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index = binary_search_insertion(nums, target)
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print(f"元素 {target} 的插入点的索引为 {index}")
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