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Update worst_best_time_complexity,
leetcode_two_sum
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@ -6,7 +6,7 @@
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#include "../include/include.h"
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/* 暴力解法 */
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/* 方法一:暴力枚举 */
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int *twoSumBruteForce(int *nums, int numsSize, int target, int *returnSize) {
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for (int i = 0; i < numsSize; ++i) {
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for (int j = i + 1; j < numsSize; ++j) {
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@ -49,7 +49,7 @@ void insert(hashTable *h, int key, int val) {
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}
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}
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/* 方法二:辅助哈希表 */
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int *twoSumHashTable(int *nums, int numsSize, int target, int *returnSize) {
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hashTable *hashtable = NULL;
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for (int i = 0; i < numsSize; i++) {
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@ -27,6 +27,8 @@ int *randomNumbers(int n) {
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/* 查找数组 nums 中数字 1 所在索引 */
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int findOne(int *nums, int n) {
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for (int i = 0; i < n; i++) {
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// 当元素 1 在数组头部时,达到最佳时间复杂度 O(1)
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// 当元素 1 在数组尾部时,达到最差时间复杂度 O(n)
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if (nums[i] == 1) return i;
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}
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return -1;
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