fix binary_search_tree code

This commit is contained in:
krahets
2023-08-31 02:31:31 +08:00
parent f7ab4797bf
commit 628d8a516b
14 changed files with 195 additions and 227 deletions

View File

@ -13,33 +13,18 @@ from modules import *
class BinarySearchTree:
"""二叉搜索树"""
def __init__(self, nums: list[int]):
def __init__(self):
"""构造方法"""
nums.sort()
self.root = self.build_tree(nums, 0, len(nums) - 1)
# 初始化空树
self.__root = None
def build_tree(
self, nums: list[int], start_index: int, end_index: int
) -> TreeNode | None:
"""构建二叉搜索树"""
if start_index > end_index:
return None
# 将数组中间节点作为根节点
mid = (start_index + end_index) // 2
root = TreeNode(nums[mid])
# 递归建立左子树和右子树
root.left = self.build_tree(
nums=nums, start_index=start_index, end_index=mid - 1
)
root.right = self.build_tree(
nums=nums, start_index=mid + 1, end_index=end_index
)
return root
def get_root(self) -> TreeNode | None:
"""获取二叉树根节点"""
return self.__root
def search(self, num: int) -> TreeNode | None:
"""查找节点"""
cur: TreeNode | None = self.root
cur = self.__root
# 循环查找,越过叶节点后跳出
while cur is not None:
# 目标节点在 cur 的右子树中
@ -55,12 +40,12 @@ class BinarySearchTree:
def insert(self, num: int):
"""插入节点"""
# 若树为空,直接提前返回
if self.root is None:
# 若树为空,则初始化根节点
if self.__root is None:
self.__root = TreeNode(num)
return
# 循环查找,越过叶节点后跳出
cur, pre = self.root, None
cur, pre = self.__root, None
while cur is not None:
# 找到重复节点,直接返回
if cur.val == num:
@ -72,7 +57,6 @@ class BinarySearchTree:
# 插入位置在 cur 的左子树中
else:
cur = cur.left
# 插入节点
node = TreeNode(num)
if pre.val < num:
@ -83,11 +67,10 @@ class BinarySearchTree:
def remove(self, num: int):
"""删除节点"""
# 若树为空,直接提前返回
if self.root is None:
if self.__root is None:
return
# 循环查找,越过叶节点后跳出
cur, pre = self.root, None
cur, pre = self.__root, None
while cur is not None:
# 找到待删除节点,跳出循环
if cur.val == num:
@ -108,14 +91,14 @@ class BinarySearchTree:
# 当子节点数量 = 0 / 1 时, child = null / 该子节点
child = cur.left or cur.right
# 删除节点 cur
if cur != self.root:
if cur != self.__root:
if pre.left == cur:
pre.left = child
else:
pre.right = child
else:
# 若删除节点为根节点,则重新指定根节点
self.root = child
self.__root = child
# 子节点数量 = 2
else:
# 获取中序遍历中 cur 的下一个节点
@ -131,10 +114,13 @@ class BinarySearchTree:
"""Driver Code"""
if __name__ == "__main__":
# 初始化二叉搜索树
nums = list(range(1, 16)) # [1, 2, ..., 15]
bst = BinarySearchTree(nums=nums)
bst = BinarySearchTree()
nums = [8, 4, 12, 2, 6, 10, 14, 1, 3, 5, 7, 9, 11, 13, 15]
# 请注意,不同的插入顺序会生成不同的二叉树,该序列可以生成一个完美二叉树
for num in nums:
bst.insert(num)
print("\n初始化的二叉树为\n")
print_tree(bst.root)
print_tree(bst.get_root())
# 查找节点
node = bst.search(7)
@ -143,17 +129,17 @@ if __name__ == "__main__":
# 插入节点
bst.insert(16)
print("\n插入节点 16 后,二叉树为\n")
print_tree(bst.root)
print_tree(bst.get_root())
# 删除节点
bst.remove(1)
print("\n删除节点 1 后,二叉树为\n")
print_tree(bst.root)
print_tree(bst.get_root())
bst.remove(2)
print("\n删除节点 2 后,二叉树为\n")
print_tree(bst.root)
print_tree(bst.get_root())
bst.remove(4)
print("\n删除节点 4 后,二叉树为\n")
print_tree(bst.root)
print_tree(bst.get_root())