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13
docs-en/chapter_computational_complexity/time_complexity.md
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@ -1737,7 +1737,7 @@ For instance, in bubble sort, the outer loop runs $n - 1$ times, and the inner l
int count = 0; // 计数器
// 外循环：未排序区间为 [0, i]
for (int i = nums.Length - 1; i > 0; i--) {
// 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
// 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
for (int j = 0; j < i; j++) {
if (nums[j] > nums[j + 1]) {
// 交换 nums[j] 与 nums[j + 1]
@ -1781,7 +1781,7 @@ For instance, in bubble sort, the outer loop runs $n - 1$ times, and the inner l
var count = 0 // 计数器
// 外循环：未排序区间为 [0, i]
for i in stride(from: nums.count - 1, to: 0, by: -1) {
// 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
// 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
for j in 0 ..< i {
if nums[j] > nums[j + 1] {
// 交换 nums[j] 与 nums[j + 1]
@ -1871,9 +1871,10 @@ For instance, in bubble sort, the outer loop runs $n - 1$ times, and the inner l
/* 平方阶（冒泡排序） */
fn bubble_sort(nums: &mut [i32]) -> i32 {
let mut count = 0; // 计数器
// 外循环：未排序区间为 [0, i]
for i in (1..nums.len()).rev() {
// 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
// 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
for j in 0..i {
if nums[j] > nums[j + 1] {
// 交换 nums[j] 与 nums[j + 1]
@ -1921,7 +1922,7 @@ For instance, in bubble sort, the outer loop runs $n - 1$ times, and the inner l
var i: i32 = @as(i32, @intCast(nums.len)) - 1;
while (i > 0) : (i -= 1) {
var j: usize = 0;
// 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
// 内循环：将未排序区间 [0, i] 中的最大元素交换至该区间的最右端
while (j < i) : (j += 1) {
if (nums[j] > nums[j + 1]) {
// 交换 nums[j] 与 nums[j + 1]
@ -2792,10 +2793,10 @@ Linear-logarithmic order often appears in nested loops, with the complexities of
return 1;
}
let mut count = linear_log_recur(n / 2.0) + linear_log_recur(n / 2.0);
for _ in 0 ..n as i32 {
for _ in 0..n as i32 {
count += 1;
}
return count
return count;
}
```