Add implementation of array binary tree.

Rewrite the tree serialization and deserialization methods.
Add applications of array and linked list.
This commit is contained in:
krahets
2023-07-19 16:09:27 +08:00
parent c68f18e480
commit 4e13755023
26 changed files with 680 additions and 178 deletions

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@ -3,13 +3,13 @@
from __future__ import annotations
# Import common libs here to simplify the codes by `from module import *`
from .linked_list import (
from .list_node import (
ListNode,
list_to_linked_list,
linked_list_to_list,
get_list_node,
)
from .binary_tree import TreeNode, list_to_tree, tree_to_list, get_tree_node
from .tree_node import TreeNode, list_to_tree, tree_to_list, get_tree_node
from .vertex import Vertex, vals_to_vets, vets_to_vals
from .print_util import (
print_matrix,

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@ -1,72 +0,0 @@
"""
File: binary_tree.py
Created Time: 2021-12-11
Author: Krahets (krahets@163.com)
"""
from collections import deque
class TreeNode:
"""Definition for a binary tree node"""
def __init__(self, val: int = 0):
self.val: int = val # 节点值
self.height: int = 0 # 节点高度
self.left: TreeNode | None = None # 左子节点引用
self.right: TreeNode | None = None # 右子节点引用
def list_to_tree(arr: list[int]) -> TreeNode | None:
"""Generate a binary tree with a list"""
if not arr:
return None
i = 0
root = TreeNode(arr[0])
queue: deque[TreeNode] = deque([root])
while queue:
node: TreeNode = queue.popleft()
i += 1
if i >= len(arr):
break
if arr[i] != None:
node.left = TreeNode(arr[i])
queue.append(node.left)
i += 1
if i >= len(arr):
break
if arr[i] != None:
node.right = TreeNode(arr[i])
queue.append(node.right)
return root
def tree_to_list(root: TreeNode | None) -> list[int]:
"""Serialize a tree into an array"""
if not root:
return []
queue: deque[TreeNode] = deque()
queue.append(root)
res: list[int] = []
while queue:
node: TreeNode | None = queue.popleft()
if node:
res.append(node.val)
queue.append(node.left)
queue.append(node.right)
else:
res.append(None)
return res
def get_tree_node(root: TreeNode | None, val: int) -> TreeNode | None:
"""Get a tree node with specific value in a binary tree"""
if not root:
return
if root.val == val:
return root
left: TreeNode | None = get_tree_node(root.left, val)
right: TreeNode | None = get_tree_node(root.right, val)
return left if left else right

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@ -1,5 +1,5 @@
"""
File: linked_list.py
File: list_node.py
Created Time: 2021-12-11
Author: Krahets (krahets@163.com)
"""

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@ -4,8 +4,8 @@ Created Time: 2021-12-11
Author: Krahets (krahets@163.com), msk397 (machangxinq@gmail.com)
"""
from .binary_tree import TreeNode, list_to_tree
from .linked_list import ListNode, linked_list_to_list
from .tree_node import TreeNode, list_to_tree
from .list_node import ListNode, linked_list_to_list
def print_matrix(mat: list[list[int]]) -> None:

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@ -0,0 +1,80 @@
"""
File: tree_node.py
Created Time: 2021-12-11
Author: Krahets (krahets@163.com)
"""
from collections import deque
class TreeNode:
"""二叉树节点类"""
def __init__(self, val: int = 0):
self.val: int = val # 节点值
self.height: int = 0 # 节点高度
self.left: TreeNode | None = None # 左子节点引用
self.right: TreeNode | None = None # 右子节点引用
# 序列化编码规则请参考:
# https://www.hello-algo.com/chapter_tree/array_representation_of_tree/
# 二叉树的数组表示:
# [1, 2, 3, 4, None, 6, 7, 8, 9, None, None, 12, None, None, 15]
# 二叉树的链表表示:
# /——— 15
# /——— 7
# /——— 3
# | \——— 6
# | \——— 12
# ——— 1
# \——— 2
# | /——— 9
# \——— 4
# \——— 8
def list_to_tree_dfs(arr: list[int], i: int) -> TreeNode | None:
"""将列表反序列化为二叉树:递归"""
# 如果索引超出数组长度,或者对应的元素为 None返回 None
if i < 0 or i >= len(arr) or arr[i] is None:
return None
# 构建当前节点
root = TreeNode(arr[i])
# 递归构建左右子树
root.left = list_to_tree_dfs(arr, 2 * i + 1)
root.right = list_to_tree_dfs(arr, 2 * i + 2)
return root
def list_to_tree(arr: list[int]) -> TreeNode | None:
"""将列表反序列化为二叉树"""
return list_to_tree_dfs(arr, 0)
def tree_to_list_dfs(root: TreeNode, i: int, res: list[int]) -> list[int]:
"""将二叉树序列化为列表:递归"""
if root is None:
return
if i >= len(res):
res += [None] * (i - len(res) + 1)
res[i] = root.val
tree_to_list_dfs(root.left, 2 * i + 1, res)
tree_to_list_dfs(root.right, 2 * i + 2, res)
def tree_to_list(root: TreeNode | None) -> list[int]:
"""将二叉树序列化为列表"""
res = []
tree_to_list_dfs(root, 0, res)
return res
def get_tree_node(root: TreeNode | None, val: int) -> TreeNode | None:
"""Get a tree node with specific value in a binary tree"""
if not root:
return
if root.val == val:
return root
left: TreeNode | None = get_tree_node(root.left, val)
right: TreeNode | None = get_tree_node(root.right, val)
return left if left else right